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Damm [24]
3 years ago
8

Write each phrase as an algebraic expression.

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0
The answers are:
4) 5x
5) x+10
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I need help with this
DedPeter [7]

I remember some of this from 6th grade!
a.) the 7th graders have a smaller range compared to the 8th graders.
c.) 30 and 18 are the medians. Subtract them and you get 12.
Hope I could help partially
6 0
3 years ago
Find the distance between the points ( 19 , 16 ) and ( − 13, 10 )
Inessa [10]

Answer:

\sqrt{1060}=32.55..... or 32.6

Step-by-step explanation:

\sqrt{(-13-19)^2+(10-16)^2}

\sqrt{(-32)^2+(-6)^2}

\sqrt{1024+36}

\sqrt{1060}=32.55..... or 32.6

hope this helps

7 0
3 years ago
Lan Ventor designs a new board game and offers the design to Paddington Games p.l.c.
Andrej [43]

In order to make the offer attractive such that it would earn £25,000 for Ian Vector, Paddington Games would have to sell 460 games.

The game can be sold for £25,000 or for £2,000 and then a fee of £50 for every game sold.

In order for the amount to be the same, the amount from games sold will have to equal the difference between the £25,000 and the £2,000.

Difference is:

= 25,000 - 2,000

= £23,000

The <u>number of games to be sold</u> is:

= Difference / Amount per game

= 23,000 / 50

= 460 games

In conclusion, 460 games need to be sold to make the offer attractive.

<em>Find out more at brainly.com/question/2865277.</em>

5 0
2 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0
1 year ago
1.What basic trigonometric identity would you use to verify that cot x sin x = cos x? . .
zavuch27 [327]
1 ) cot x * sin x = cos x
(cos x / sin x) * sin x = cos x 
cos x = cos x
Answer: B ) cot x = cos x / sin x
2 ) ( sin² x + cos² x ) / cos x = sec x
1/cos x = sec x
sec x = sec x
Answer: C ) cos² x + sin² x = 1
3 0
3 years ago
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