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klio [65]
3 years ago
15

Solve by completing the square. x2 + 12x + 8 = 0

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0
X= -4/7 please help me out now and answer number 10 on my questions
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Simplify: (-10)^4<br> A.-6<br> B.-40<br> C.10,000<br> D.-10,000
hodyreva [135]

C will be your answer

<h2>C. 10,000</h2>
6 0
3 years ago
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the point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y 7 = (x – 10). what is the standa
expeople1 [14]
y+7=(x-10)\\\\y+7=x-10\\\\x-y-10-7=0\\\\\boxed{x-y-17=0}
6 0
4 years ago
Help me please thank you
docker41 [41]

After I read the equation, I remembered that anything to the power of 1 is itself. so f(x)=2-9

2-9= -7

therefore, f(x)= -7

if x=1, then the f(x) must be Y

<u><em>therefore, your answer should be y= -7</em></u>

6 0
3 years ago
Which logarithmic equation is equivalent to the exponential equation below? e^4x = 5 (the x is part of the ^4 exponent) A. log 5
GalinKa [24]
Keep in mind that "ln" is just a shortcut for the logarithm with a base of "e".

\bf \textit{exponential form of a logarithm}\\\\&#10;log_{{  a}}{{ ( b)}}=y \implies {{  a}}^y={{  b}}\qquad\qquad &#10;%  exponential notation 2nd form&#10;{{  a}}^y={{  b}}\implies log_{{  a}}{{(b)}}=y \\\\&#10;-------------------------------\\\\&#10;e^{4x}=5\implies log_e(5)=4x\implies ln(5)=4x
8 0
4 years ago
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Glynn's car has a 18 gallon gas tank. He travels 450 miles. What is the least miles per gallon this trip? Write and solve an ine
Ratling [72]

The least miles per gallon this trip is 25 miles per gallon

<h3>How to determine the least miles per gallon?</h3>

The given parameters are:

Distance = 450 miles

Tank size = 18 gallons

The least miles per gallon this trip is calculated as:

Miles per gallon = Distance/Tank size

This gives

Miles per gallon = 450/18

Evaluate the quotient

Miles per gallon =25

Represent as an inequality

x >= 25

Hence, the least miles per gallon this trip is 25 miles per gallon

Read more about speed at:

brainly.com/question/4931057

#SPJ1

4 0
2 years ago
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