Answer:
E. 0.759
Step-by-step explanation:
You can take this right triangle to have a base length side LM , height of LN and a hypotenuse of MN
The sine of angle ∠LMN is 0.759, find the value of ∠LMN

∠LMN=49.38°
Find angle ∠LNM
You know sum of angles in a triangle add up to 180°, given that this is a right-triangle, the base angle is 90° hence
∠LNM=180°-(90°+49.38°)
∠LNM= 180°-139.38°=40.62°
Find cos 40.62°
Cos 40.62°=0.7590
Answer:
Step-by-step explanation:
We can write two equations in the two unknowns using the given relations. Let g and b represent the costs of a round of golf and a turn in the batting cage, respectively.
5g +4b = 60 . . . . . Sylvester's expense
3g +6b = 45 . . . . . Lin's expense
Dividing the second equation by 3 gives ...
g +2b = 15 ⇒ 2b = 15 -g
Substituting into the first equation, we have ...
5g +2(2b) = 60
5g +2(15 -g) = 60 . . . . . substitute for 2b
3g = 30 . . . . . . . . . subtract 30, collect terms
g = 10 . . . . . . . divide by 3
__
2b = 15 -10 = 5 . . . . use the value of g to find b
b = 2.5 . . . . . . . . divide by 2
Mini golf costs $10 per round; batting cages cost $2.50 per turn.
Probs a decrease of 37 boiiii
Answer:
the third one
Step-by-step explanation:
CPI in 1960 = 29.6
CPI in 1980 = 82.4
Growth (%) in CPI =
× 100
⇒ Growth (%) in CPI =
× 100
⇒ Growth (%) in CPI = 178.3783.. %
⇒ Growth (%) in CPI = 178.4%
Now, we know that price of frozen chicken pie in 1960 = $0.28
Also, we know that over 1960 to 1980, frozen chicken pie price grew at the same rate as CPI
Hence, Price of Chicken Pie in 1980 = Price of Chicken Pie in 1960 × (1 + Growth in CPI)
⇒ Price of Chicken Pie in 1980 = 0.28 × (1 + 178.4%)
⇒ Price of Chicken Pie in 1980 = 0.28 + (0.28 × 178.4%)
⇒ Price of Chicken Pie in 1980 = 0.28 + 0.49952
⇒ Price of Chicken Pie in 1980 = 0.28 + 0.50
⇒ Price of Chicken Pie in 1980 = $0.78
Hence, price of chicken pie in 1980 would be ~$0.78