Because the square has similar lengths, the equation would be
(7x-2)(7x-2)
We can use FOIL to solve this:
The area is 49x^2 - 28x + 4 in^2.
For the second one 1 mph equals 1.6 km so i’m pretty sure it would be all of them
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Answer:
-9/5
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-2-7)/(0-(-5))
m=-9/(0+5)
m=-9/5
