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3 years ago

8

Use the given information to find (a) sin (s +t), (b) tan (s+t), and (c) the quadrant of s+t costs=3/5 and cost= 15/17, s and t

quadrant IV

1 answer:

Tpy6a [65]3 years ago

3 0

i don't understand your language

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Estimate the area of tje fan if m

kati45 [8]

Answer:

Area of the given fan is 763.4 cm²

Step-by-step explanation:

Area of a sector in a circle = $\frac{\theta}{360}(\pi r^2)$

Here, angle θ = Central angle subtended by the arc

r = Radius of the circle

Since, fan is in the form of a sector of a circle with radius = 27 cm

Measure of the central angle subtended by the arc FN = ∠FAN = 120°

Area of the fan = $\frac{120}{360}(\pi )(27)^2$

= $\frac{729\pi }{3}$

= 243π

= 763.407

≈ 763.4 cm²

Therefore, area of the given fan is 763.4 cm²

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3 years ago

Which equations are equivalent of requirements -1/4(x)+3/4=12? select all that apply.

bearhunter [10]

Your really nice!!!!! I didn’t need this but I just wanted to say!

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3 years ago

At a birthday party there were 20 balloons. A few of the kids decided to pop b balloons so the parents blew up another 6 balloon

notsponge [240]

The expression could be: (20-b)+6

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3 years ago

State the rule that will result in the transformation below.<br> (x,y) maps to (?, ?)

Anna [14]

Answer:

(x,y) maps to (-y,x).

Step-by-step explanation:

Use vertex I as an example.

Pre-image I is graphed at point (-3,2), while image I' is graphed at point (-2,-3) .

In order to change between these points, the x and y coordinates must be swapped, as well as multiplying the y coordinate by -1.

8 0

3 years ago

lys-0071 [83]

Answer:

$PS=13\text{ units}$

Step-by-step explanation:

So, we know that PR is 20, SR is 11, and QS is 5.

We also know that PQ is perpendicular to QR, forming the right angle at ∠Q.

We know all the side lengths except for PQ and PS (the one we want to find). Notice that if we find PQ first, we can then use the Pythagorean Theorem to find PS since we already know QS.

So, let's find PQ.

We can see that we can also use the Pythagorean Theorem on PQ. PQ, QR, and PR (the hypotenuse) will be our sides. So:

$(PQ)^2+(QR)^2=(PR)^2$

We know that PR is 20.

QR is the combined length of QS+SR, so QR is 5+11 or 16.

So, substitute:

$(PQ)^2+(16)^2=(20)^2$

Solve for PQ. Square:

$(PQ)^2+256=400$

Subtract 256 from both sides:

$(PQ)^2=144$

Take the square root of both sides:

$PQ=12$

So, the side length of PQ is 12.

Now, we can use the Pythagorean Theorem again to find PS. Notice that PQ, QS, and PS also form a right triangle, with PS being the hypotenuse. So:

$(PQ)^2+(QS)^2=(PS)^2$

We already know that QS is 5. We also just determined that PQ is 12. Substitute:

$(12)^2+(5)^2=(PS)^2$

Square:

$144+25=(PS)^2$

Add:

$169=(PS)^2$

Take the square root of both sides:

$PS=13$

Therefore, the length of PS is 13 units.

And we're done!

7 0

4 years ago