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kondor19780726 [428]

3 years ago

8

The diagram shows a door lock.

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SVETLANKA909090 [29]3 years ago

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Could i have a photo?

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During the month of April, Dora kept track of the bugs she saw in her garden. She saw a ladybug on 23 days of the month. What is

Vinvika [58]

D. 23/30 This is saying that out of 30 days, 23 of them she saw a ladybug, which means that each day, there is a 23/30 chance of finding one.

4 0

3 years ago

-3(2d)+ (-5e +6) + (3d-8) I'm standard form

Sati [7]

Answer:

−3d−5e−2

Step-by-step explanation:

7 0

3 years ago

How do I resolve this? <br> Como resuelvo esto?

Nikolay [14]

$\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ -----\\ A=144\pi \end{cases}\implies 144\pi =\pi r^2\implies \cfrac{144\pi }{\pi }=r^2 \\\\\\ 144=r^2\implies \sqrt{144}=r\implies \boxed{12=r} \\\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad C=2\pi \boxed{12}\implies C=24\pi$

4 0

3 years ago

The perimeter of the triangle shown is 412 meters. Find the length of each side.

Fudgin [204]

Answer:

x meters= 35

5x meters= 175

6x - 8 = 202

Step-by-step explanation:

x + 5x + (6x - 8)= 412

12x - 8= 412

12x = 412 + 8

12x = 420

x= 35

5x = 35× 5

= 175

6x - 8= 6(35) - 8

= 210 - 8

= 202

7 0

2 years ago

The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle

ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.

Hence, the length is $2w+6$ .

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

$A=w(2w+6)$

We can also substitute 40 in for A as it's given in the question.

$40 = w(2w+6)$

Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get

$40 = 2w^2+6w$

We can make the equation simpler by dividing both sides by 2.

$20 = w^2+3w$

Subtracting both sides by 20 will make the left-hand side 0.

$0=w^2+3w-20$

Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

$w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}$

$w= \frac{-3\pm\sqrt{9+80}}{2}$

$w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}$

Since the second solution results in a negative number, it cannot be the length of w.

$w=\frac{-3+\sqrt{89}}{2}\approx3.217$

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

$l=2(3.217)+6$

$l=12.434$

The length of this rectangle is 12.434 cm.

6 0

2 years ago