The answer is d lol have a good day
Exponentail thingies
easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0
now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero
5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1
5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4
x=log₅1 and/or log₅4
second quesiton
same thing
1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero
2^x-8=9
2^x=8
x=3
2^x-2=0
2^x=2
x=1
x=3 or 1
first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3
x^2 +9x +25 + 44/x-2
Step-by-step explanation:
Answer: 22 people will be riding the lady trip on the ferry
<span>We already know that angles ECS and TRS are congruent, because they are both right angles (given). We also know that angles CSE and RST are congruent because they are vertical angles and vertical angles are always congruent. That gives us two sets of congruent angles. We just need to know something about one pair of sides to prove the two triangles congruent to each other. I do question the order of the letters in the names of the triangles--if that's really the order the letters are written in the problem, then we would need to know that ES is congruent to RT or that CS is congruent to ST. If the order of the letters of the names of the triangles is a little different we would need to know that CS is congruent to RS or that any of the other sides that appear to match are actually congruent. </span>
