37+53=90 so 180-90=90
x=90
x= 180-(37+53)
x= 90 ✅
Let

be the solid. Then the volume is

which follows from the facts that

(by computing the Jacobian)
and

(we take the positive solution, since it's clear that

lies above the

-

plane)

(again, taking the positive root for the same reason)





Answer:
20 side polygon: 180 x (20 -2)
Step-by-step explanation:
A n side polygon can be divided into n-2 triangles
each triangle has 180°
n-2 triangles have 180 x (n-2) degrees
From the given information, we get the value of ABC = 120°.
<h3>How to estimate the value of ABC?</h3>
Given: In the figure, O exists the center of the circle and OABC exists as a parallelogram.
Now, the radius of the circle exists
OA = OB = OC
Opposite sides of a parallelogram are equal
AB = OC and OA = BC
In ∆OAB,
OA = OB = AB and,
In ∆OCB,
OC = OB = BC
Therefore, ∆OAB and ∆OCB exist in equilateral triangles.
All angles of an equilateral triangle are equivalent to 60°.
Hence, ∠ABC = ∠OBA + ∠OBC
∠ABC = 60° + 60°
∠ABC = 120°
Therefore, the value of ∠ABC = 120°.
To learn more about parallelogram refer to:
brainly.com/question/24291122
#SPJ9
Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)