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Brums [2.3K]
3 years ago
14

How many edges are there? plz no links

Mathematics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

9

Step-by-step explanation:

maw [93]3 years ago
6 0

Answer:

9

Step-by-step explanation:

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Peggy wants to run 5 miles in less than 60 minutes. What inequality shows what her rate should be ?
sleet_krkn [62]
The inequality that her rate should be is
<span>5 > 60</span>
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3 years ago
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Help! In parallelogram LMNO below, find the length of MO
pashok25 [27]

Answer:

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.

5y - 8 = 3y + 1              Add 8 to both sides

5y = 3y + 1 + 8             Subtract 3y from both sides

5y - 3y = 9                   Combine

2y = 9                          Divide by 2

2y/2 =9/2  

y = 4. 5

5y - 8 =

5(4.5) - 8 =

22.5 - 8 =

14.5

That represents 1/2 of MO

MO = 2 * 14.5

MO = 29

5 0
2 years ago
HELP!! I HAVE THE ANSWERS I Just NEED TO SHOW THE WORK!!
tino4ka555 [31]

Answer:

8 times 5 on each side

Step-by-step explanation:

4 0
2 years ago
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The figure below is a parallelogram. AB = 5 cm and BC = 3 cm. Find angle ABC
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Step-by-step explanation:

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5 0
2 years ago
a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th
hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in ^{5000}C_{10} ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in ^{1000}C_3 \times {4000}C_7 ways.

Possibility 2:  <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in ^{1000}C_2 \times ^{4000}C_8  ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in ^{1000}C_1 \times^{4000}C_9 ways.

Possibility 4:  <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in ^{1000}C_0 \times^{4000}C_{10} ways.

Hence, the required probability is \frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }.

6 0
2 years ago
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