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Brums [2.3K]
3 years ago
14

How many edges are there? plz no links

Mathematics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

9

Step-by-step explanation:

maw [93]3 years ago
6 0

Answer:

9

Step-by-step explanation:

You might be interested in
!help asap!
Ede4ka [16]
37+53=90 so 180-90=90
x=90

x= 180-(37+53)
x= 90 ✅
4 0
3 years ago
Use cylindrical coordinates. find the volume of the solid that is enclosed by the cone z = x2 + y2 and the sphere x2 + y2 + z2 =
sashaice [31]
Let R be the solid. Then the volume is

\displaystyle\iiint_R\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta

which follows from the facts that

\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta
(by computing the Jacobian)

and

z=x^2+y^2=r^2\implies z+z^2=72\implies z=-9\text{ or }z=8
(we take the positive solution, since it's clear that R lies above the x-y plane)
r^2+z^2=72\implies z=\pm\sqrt{72-r^2}
(again, taking the positive root for the same reason)
z=r^2\implies 8=r^2\implies r=\sqrt8

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}r(\sqrt{72-r^2}-r^2)\,\mathrm dr
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}(r\sqrt{72-r^2}-r^3)\,\mathrm dr
=\dfrac{32(27\sqrt2-35)\pi}3
7 0
3 years ago
Can some one help me with this math problem and explain their self's as well?
yaroslaw [1]

Answer:

20 side polygon: 180 x (20 -2)

Step-by-step explanation:

A n side polygon can be divided into n-2 triangles

each triangle has 180°

n-2 triangles have 180 x (n-2) degrees

3 0
4 years ago
In a given figure if o is the centre of circle and oabc is a parallelogram find the value of abc
ahrayia [7]

From the given information, we get the value of ABC = 120°.

<h3>How to estimate the value of ABC?</h3>

Given: In the figure, O exists the center of the circle and OABC exists as a parallelogram.

Now, the radius of the circle exists

OA = OB = OC

Opposite sides of a parallelogram are equal

AB = OC and OA = BC

In ∆OAB,

OA = OB = AB and,

In ∆OCB,

OC = OB = BC

Therefore, ∆OAB and ∆OCB exist in equilateral triangles.

All angles of an equilateral triangle are equivalent to 60°.

Hence, ∠ABC = ∠OBA + ∠OBC

∠ABC = 60° + 60°

∠ABC = 120°

Therefore, the value of ∠ABC = 120°.

To learn more about parallelogram refer to:

brainly.com/question/24291122

#SPJ9

6 0
2 years ago
A computer assembling company receives 24% of parts from supplier X, 36% of partsfrom supplier Y, and the remaining 40% of parts
Ivan

Answer:

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

Step-by-step explanation:

denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier

then

P(A)= ∑ P(Bi)*P(C) with i from 1 to 3

P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125

from the theorem of Bayes

P(Cz/A)= P(Cz∩A)/P(A)

where

P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained

P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100

therefore

P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

8 0
3 years ago
Read 2 more answers
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