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3 years ago

A clock loses 5 seconds every 12 minutes. At this rate, how many minutes will the clock lose in a 24-hour period?

Mathematics

2 answers:

Airida [17]3 years ago

5 0

10 minutes b/c some one already put an answer

Bingel [31]3 years ago

3 0

Answer:

10 minutes

Step-by-step explanation:

24h = 24x60min = 1440min

5 sec ............. 12 min

x sec ..........1440 min

x = 1440*5/12 = 600 sec = 10 min

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2.) 4x + 8.2 ≤ 32.2 * A. x ≤ 60 B. x ≥ 6 C. x ≥ 60 D. x ≤ 6

Inga [223]

Answer:

Step-by-step explanation:

Given

4x + 8.2 ≤ 32.2 ( subtract 8.2 from both sides )

4x ≤ 24 ( divide both sides by 4 )

x ≤ 6 → D

6 0

3 years ago

Read 2 more answers

A 4th grade class took a field trip to a science museum. There are 24 students in the class. Each student

brilliants [131]

Answer:

$432

Step-by-step explanation:

Students:24

Ticket:$9

Lunchbox:$9

9+9=18

24x18=$432

4 0

2 years ago

Someone help on the first and number

Lelu [443]

It is a mixed number because mixed mumbers have higher numerator than the denominator

3 0

3 years ago

Read 2 more answers

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago

3. What is wrong with the following statement? If d/e = f, then d multiplied by f = e.f should be divided by e.F and e should be

Molodets [167]

the initial statement is:

$\frac{d}{e}=f$

and then:

$d\cdot f=e$

So the second statement is false because f should be multiply by e, not by d so is option C)

4 0

1 year ago