What is the common ratio between successive terms in the sequence?
1 answer:
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Answer:
The home would be worth $249000 during the year of 2012.
Step-by-step explanation:
The price of the home in t years after 2004 can be modeled by the following equation:
In which P(0) is the price of the house in 2004 and r is the growth rate.
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.
This means that
$172000 in 2004
This means that
What year would the home be worth $ 249000 ?
t years after 2004.
t is found when P(t) = 249000. So
2004 + 8.05 = 2012
The home would be worth $249000 during the year of 2012.
26,862 divided by 407 is 66
Here's the long division way that shows how you get 66
Here's the long division way that shows how you get 66