Answer:
30 ways
Step-by-step explanation:
Given the following information:
- 3 different sandwiches
- 2 different salads
- 5 different drinks
Let assume that the combo contains: 1 sandwich, 1 salad, and 1 drink
Hence, we have:
- The total possible ways of choosing sandwiches she can choose is: 3
- The total possible ways of choosing salads she can choose is: 2
- The total possible ways of choosing drinks she can choose is: 5
=> Total ways = 3*5*2 = 30 ways or there are 30 different combos Keisha can choose
Hope it will find you well.
Yes it can and the answer would be 0.5
Terminating decimals are numbers that never stop going after the period. Such an example would be 10/3 which would give 3.333333 indefinitely. 1/2 gives a whole number, that is, 0.5
Answer:
Step-by-step explanation: candy
Answer:
B:0.16
Step-by-step explanation:
Because you keep adding it and you will soon have 4.24 liters
This is quite a complex problem. I wrote out a really nice solution but I can't work out how to put it on the website as the app is very poorly made. Still, I'll just have to type it all in...
Okay so you need to use a technique called logarithmic differentiation. It seems quite unnatural to start with but the result is very impressive.
Let y = (x+8)^(3x)
Take the natural log of both sides:
ln(y) = ln((x+8)^(3x))
By laws of logarithms, this can be rearranged:
ln(y) = 3xln(x+8)
Next, differentiate both sides. By implicit differentiation:
d/dx(ln(y)) = 1/y dy/dx
The right hand side is harder to differentiate. Using the substitution u = 3x and v = ln(x+8):
d/dx(3xln(x+8)) = d/dx(uv)
du/dx = 3
Finding dv/dx is harder, and involves the chain rule. Let a = x+ 8:
v = ln(a)
da/dx = 1
dv/da = 1/a
By chain rule:
dv/dx = dv/da * da/dx = 1/a = 1/(x+8)
Finally, use the product rule:
d/dx(uv) = u * dv/dx + v * du/dx = 3x/(x+8) + 3ln(x+8)
This overall produces the equation:
1/y * dy/dx = 3x/(x+8) + 3ln(x+8)
We want to solve for dy/dx, achievable by multiplying both sides by y:
dy/dx = y(3x/(x+8) + 3ln(x+8))
Since we know y = (x+8)^(3x):
dy/dx = ((x+8)^(3x))(3x/(x+8) + 3ln(x+8))
Neatening this up a bit, we factorise out 3/(x+8):
dy/dx = (3(x+8)^(3x-1))(x + (x+8)ln(x+8))
Well wasn't that a marathon? It's a nightmare typing that in, I hope you can follow all the steps.
I hope this helped you :)
