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MA_775_DIABLO [31]
2 years ago
15

Murray tossed a coin 120 times. The coin landed on heads 54 times. Find the theoretical and experimental probability that the ne

xt toss will land on heads.
Mathematics
1 answer:
elena-s [515]2 years ago
5 0
46% the next one will land on heads
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What is 2/3 + 1/2<br> In fraction form please .
vazorg [7]

Answer: 7/6 or 1 and 1/6

Step-by-step explanation:

2     1

  +

3     2

you have to make them have the same denominators(the number on the bottom of a fraction)

2/3--> 4/6

1/2---> 3/6

4/6+3/6=7/6 or 1 and 1/6

7 0
2 years ago
Read 2 more answers
When solving for y, in which step did Ramon make a mistake?
Charra [1.4K]
It should be e I don’t kn
7 0
2 years ago
Please help me find it i will give 20 pts
jolli1 [7]

Answer:

a) 23.5619449 m^2     b) 351.8583772 cm^2      c) 75.39822369 cm^2

Step-by-step explanation:

a):

SA = 2πr^2+2πr

r= 3/2 = 1.5

SA= 2π*1.5^2 + 2π*1.5

SA= 15/2 ∏

SA= 23.5619449 m^2 round it as you want

b): Same steps as "a" but rather than m^2 it is cm^2

the answer will be:

SA= 112π

SA= 351.8583772 cm^2  round it as you want

c): the radius is already given so just place it in place of r

SA= 2π*3^2 + 2π*3

SA= 24π

SA= 75.39822369 cm^2

5 0
2 years ago
Please help!<br> show in dept steps
rewona [7]

Given:

54.1 \times  \sqrt{15.11}

To remove decimal, divide first equation by 10 and second equation by 100

=  >  \frac{541}{10} \times  \sqrt{ \frac{1511}{100}}

Now opening the root,

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{ \sqrt{100}}

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{ \sqrt{10^{2} }}

=  >  \frac{541}{10} \times  \frac{ \sqrt{1511} }{10}

=  >  \frac{54 \times  \sqrt{1511} }{10 \times 10}

=  >  \frac{541 \sqrt{1511} }{100}

Hence, the answer is \frac{541 \sqrt{1511} }{100}

5 0
2 years ago
Olive's solar powered scooter travels at a rate of 30 miles per hour. What equation can she use to calculate her distance with r
avanturin [10]
S=((u+v)/2)t
S=displacement (distance)
U=initial velocity
V=final velocity
T=time
8 0
3 years ago
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