Need help in this question asap srry i need points
Answer:
c.15+2z/6x-12y
f.7a+b/4a-6b
Step-by-step explanation:
z+1/x-2y - 2x-3/2x-4y + z/3x-6y
z+1/x-2y - 2x-3/2(x-2y) + z/3(x-2y)
6(z+1)-3(2z-3)+2z
15+2z/6x-12y
3a/2a-3b - a+b/2(-3b+2a)
6a+a+b/2(2a-3b)
7a+b/4a-6b
Answer:
n=4
JK=12
KL=13
Step-by-step explanation:
Since JL=25 and JL=3n+5n-7
Then
3n+5n-7=25 simplifying we get
8n-7=25 subtracting 7 from both sides
8n=32 dividing both sides by 8
n=4
JK?
JK=3n bt n=4
JK=3*4
JK=12
KL?
KL=5n-7
KL=5*4-7
KL=13
Answer:
The two numbers are -419 and -2095.
Step-by-step explanation:
5x=y
x-y=1676
----------------
x-5x=1676
-4x=1676
x=1676/-4
x=-419
5(-419)=y
y=-2095
Answer:
35.25
Step-by-step explanation:
Give the data set:
23 37 49 34 35 41 40 26 32 22 38 42
We are expected to calculate the midquartile of the given data set.
22 23 26 32 34 35 37 38 40 41 42 49
First step is to find the lower quartile which comprises of
22 23 26 32 34 35
Here the Q1 is (26+32)/2 = 58/2= 29
Second step to find the upper quartile which comprises of
37 38 40 41 42 49
Here the Q3 is (40+41) /2 = 81/2 = 41.5
Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5
= (29+41.5)/2
= (70.5) /2 = 35.25
