4/9 (x+3)=g. Solve for X. State any restrictions on the variables

In the diagram, point X is the centroid. If EX=8, what is the length of XC ?

Phoenix [80]

Answer:

16

Step-by-step explanation:

If X is the centroid that means that EC is a median along with the other lines that intersect inside the triangle. Medians drawn from a triangle have a special rule; this rule is that all medians have a 2:1 ratio between the different sections of one median. For example, EC is one median with the two sections XC and EX. Therefore XC and EX have a 2:1, with the 2 representing the longer section closest to the vertex. This means that XC is double EX, so to find XC simply double EX measurement, which is 8. So XC must equal 16.

7 0

2 years ago

Use Newton's method to approximate a root of the equation 3x^7+2x^4+3=0 Let x1 =1 be the initial approximation. The second appro

liubo4ka [24]

Answer:

3.3

Step-by-step explanation:

logging in and answering

5 0

2 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

2 years ago

Help me please ASAP

uranmaximum [27]

Perimeter is 24.

Length is 4 greater than the width.

Let's use 'x' for width

we can write this as x+4 + x+4 + x + x

x+4 being the width+4 and x being the width

There are 4 sides to a rectangle so you are adding 4 values

Two length and two widths

so we can then combine the two lengths to make 2x+8

and then combine the two widths to make 2x

Then put it together. 2x+2x+8= 4x+8

4x+8=24

Subtract 8 from both sides

4x=16

divide both sides by 4

x=4

The width is 4.

6 0

3 years ago

Ok I need help ASAP pls like right now points are going giving and mark brainless pls help I need answers for 1,2,3

Schach [20]

Answer:

1. 30 student

2. 120 student's didn't vote

3. 7 quarters

Step-by-step explanation:

1. first, see how many games can be played:

45÷3 = 15

then, multiply the number of games by two because 2 students can play per game

15 • 2 = 30

2. first, figure out what percent of students did not vote:

100 - 60 = 40%

then, multiply the number of students total (300) by the decimal of the percent that did not vote to find the number of students who didn't vote:

300 • .40 = 120 student's didn't vote

3. first, find how much 9 dimes is:

1 dime = $0.10

9 dimes = 9 • $0.10 = $0.90

then, find how much money kerry had:

$2.65 - $0.90 = $1.75

finally, find out how many quarters kerry had by dividing the amount of money she had by the worth of a quarter:

1 quarter = $0.25

$1.75 ÷ $0.25 = 7 quarters

8 0

2 years ago