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Firlakuza [10]
3 years ago
13

what algorithm (rule) will produce the correct result for the sum "a+b" where a and b each represent any rational number.

Mathematics
1 answer:
Leokris [45]3 years ago
5 0

Answer:

To find the sum of  a + b where a and b are rational number.

1. when a and b are natural numbers

just add them . for example a =3, b=8

then ,a + b = 11

2. When a and b  are whole numbers,

simply add them . for example a= 0, b=8

a+ b = 0 + 8= 8

3. When  a and b are integers

for example, a =-1 b=8,

a+ b= -1+ 8 =7,

a=-2, b= -8

a+ b= -2-8=-10

a= -6 , b=2

a+ b= -6 + 2= -4

a= 8, b= -2

a+ b= 8 +(-2) =6

I have written this because Rational number = [Integers{Whole number(Natural number)}]

now when a= Any fraction=\frac{p}{q} and b = Any fraction=\frac{u}{v}

now ,

\frac{p}{q} + \frac{u}{v}

Find L.C.M of q and v

= if q and v are Co-prime , just multiply them to find their  L.C.M.

For example 14,9. LCM=14×9=126

Otherwise, Find factors of q and v . Then take out common factors first and then multiply the remaining with with common factors.For example

q=12 and v=18

12 =2×2×3

18=2×3×3

common factor =2,3

non common=2,3

L.C.M= 2×2×3×3=36

Suppose LCM of q and v = r

then ,\frac{p}{q} + \frac{u}{v}

=\frac{{\frac{r}{q}}\times p+{\frac{r}{v}\times u}}{r}\\

= {{\frac{r}{q}}\times p+{\frac{r}{v}\times u}} = k

then ,

a + b=\frac{k}{r}





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antiseptic1488 [7]
You can solve this by putting the number of copies in the top part of the fraction. If you replace the one in the top part of 1/6 with 3, you get the fraction 3/6. Half of six is three and half of two is one, so both fractions are equal. You can test this be dividing the 3 in the top by 3 and the 6 in the bottom by three. Your result will be 1/2. Although there are three times ad many copies, each copy is three times as small, so it balances out.
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mezya [45]

Answer:

33.75

Step-by-step explanation:

45x0.75=33.75

3 0
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Andy has 310 in his account. Each week w he withdraws 30 for his expences which expression could be used if he wanted to find ou
Butoxors [25]
310-30x=y
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3 years ago
A triangle has two sides of length 15 cm and 17 cm. Select all the values of its third side that would make it a right triangle
Natali [406]

Answer:

\sqrt{514} cm, 8cm, are both options

Step-by-step explanation:

For a right triangle one can find the length of the longest side by using the Pythagorean theorem. So there are two options I can think of that if the triangle is a right triangle will work. First remember what the Pythagorean theorem is : side a^2+side b^2=hypotenuse^2

The hypotenuse is the longest side of a right triangle. So if the sides that are 15 and 17 cm are not the longest sides then the formula would be:

15^{2} +17^2=c^2\\15^2+17^2=\sqrt{514}cm

But if 17cm is the longest side then:

a^2+15^2=17^2\\8^2+15^2=17^2\\a=8cm

Hope this helps!

4 0
3 years ago
Read 2 more answers
A 6m ladder leans against a wall. The bottom of the ladder is 1.3m from the wall at time =0sec and slides away from the wall at
icang [17]

Answer:

- 0.100

Step-by-step explanation:

Length of the ladder,  H = 6 m

Distance at the bottom from the wall, B = 1.3 m

Let the distance of top of the ladder from the bottom at the wall is P

Thus,

from  Pythagoras theorem,

B² + P² = H²    .

or

B² + P² = 6²          ..............(1)      [Since length of the ladder remains constant]

at B = 1.3 m

1.3² + P² = 6²

or

P² = 36 - 1.69

or

P² = 34.31

or

P = 5.857

Now,

differentiating (1)

2B(\frac{dB}{dt})+2P(\frac{dP}{dt})=0

at t = 2 seconds

change in B = 0.3 × 2= 0.6 ft

Thus,

at 2 seconds

B = 1.3 + 0.6 = 1.9 m

therefore,

1.9² + P² = 6²

or

P = 5.69 m

on substituting the given values,

2(1.9)(0.3) + 2(5.69) × (\frac{dP}{dt}) = 0

or

1.14 + 11.38 × (\frac{dP}{dt}) = 0

or

11.38 × (\frac{dP}{dt}) = - 1.14

or

(\frac{dP}{dt}) = - 0.100

here, negative sign means that the velocity is in downward direction as upward is positive

5 0
4 years ago
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