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dlinn [17]
3 years ago
13

One number is 3 less than a second number. Twice the second number is 14 more than 3 times the first. Find the two numbers

Mathematics
1 answer:
Butoxors [25]3 years ago
8 0

Answer:

Number 1 is 10 and number 2 is 7

14/2 = 7

7 + 3 = 10

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
mr_godi [17]

Answer:

To determine the inverse of the given function, change f(x) to y, switch x and y and solve for y and f^-1(x)= ln(x+4)/2

Step-by-step explanation:

f(x) = e^2x - 4

to find the inverse let

y = e^2x - 4

Replace x and y

x = e^2y - 4

and now, solve to find value of y

x + 4 = e^2y

taking ln on both sides:

ln(x+4) = ln(e^2y)

ln(x+4) = 2y

=> y = ln(x+4)/2

=> f^-1(x)= ln(x+4)/2

So, To determine the inverse of the given function, change f(x) to y, switch x and y and solve for y and f^-1(x)= ln(x+4)/2

4 0
3 years ago
Read 2 more answers
Need help with negative fractions and multiplication
Naily [24]
What is the specific wuestion?
7 0
3 years ago
What is 10/24 as a improper fraction
Svetllana [295]

Answer:

10/24 cannot be written as an improper fraction.

Step-by-step explanation:

a faction is only an improper fraction when the numerator is a larger number than the denominator. Therefore, this fraction, 10/24, can only be simplified or transformed into a decimal.

Simplified: 5/12

Decimal: 0.416 or 0.42

I hope this was helpful!

3 0
4 years ago
Help?????????????????
seraphim [82]

Answer:

yes it does

Step-by-step explanation:

as you can see,

in a function, we don't have more than one y for a x, so here we have one y for each x. then it is

7 0
3 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
4 years ago
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