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erastovalidia [21]

2 years ago

7

The Hiking Club plans to go camping in a State park where the

1 answer:

ozzi2 years ago

5 0

Answer: Probability is 0.00205 = 0.205%

Step-by-step explanation: P(rain) = 0.71, P(no rain) = 0.29.

P(no rain in 5 days)= 0.29·0.29·0.29·0.29·0.29= 0.00205

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A car dealership has 240 cars in the parking lot and 17.5% of them are red. Of the other 6 colors in the lot, each color has the

ella [17]

234. 175 will be the anwser

7 0

3 years ago

An element with mass 130 grams decays by 22% per minute. How much of the element is remaining after 7 minutes, to the nearest 10

shepuryov [24]

22.8 grams of element will be remaining after 7 minutes

Further explanation:

Given

$Mass\ of\ element=130g\\Percentage\ of\ reduction=22\%$

The element reduces (1-22%) in one minute.

The process will be repeated 7 times for 7 minutes

If we have to calculate the amount of element after 7 minutes

then the total reduction will be: (1-22%)^7

$Remaining\ amount=130*(1-22\%)^7\\=130*(1-0.22)^7\\=130*(0.78)^7\\=130*0.18\\=22.84g\\Rounding\ off\ to\ nearest\ tenth\\=22.8g$

22.8 grams of element will be remaining after 7 minutes

Keywords: Decay, Percentage

Learn more about percentage at:

#LearnwithBrainly

6 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Helpp (please tell me if you can’t see the numbers so I can tell you them)

Ugo [173]

Answer:

-6 is the y coordinate

Step-by-step explanation:

3 0

3 years ago

If AB=BA= I then write the relation between matrix A and matrix B

butalik [34]

Answer:

If AB = BA = I, then B is inverse of A and vice-versa.

Step-by-step explanation:

Given: AB = BA = I

To find: The relation between matrix A and B.

If AB = BA = I, then B is called the inverse matrix of A and is denoted by $A^{-1}$ .

In that case, A is said to be invertible.

Also, if B is the inverse of A, then A is also the inverse of B.

Hence, the relation between A and B is that both are inverse of each other.

6 0

3 years ago