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3 years ago

Through: (-5, 4), parallel to y=--x+4

Mathematics

1 answer:

Zinaida [17]3 years ago

8 0

Answer:

y=-x-1

Step-by-step explanation:

1.) equation of line in slope-intercept form: y=4-x

2.) parallel of line is same as: m=-1

3.) equation of parallel line is: y=-x+b

4.) finding b: 4=(−1)⋅(−5)+b

b=-1

5.) therefore, equation is y=-x-1

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NetSell, a the TV remote control supplier for Lumyn Electronics, has a weekly production cost of q TV remote controls that is gi

natali 33 [55]

Answer:

a. $\frac{dC(q)}{dq} = 0.000012q^2 -0.06q + 100$

b. $\frac{dR(q)}{dq}=-0.01q+200$

$U'(2000)=-0.000012(2000)^2+0.05(2000)+100 = 152$

$U'(7000)=-0.000012(7000)^2+0.05(7000)+100 = -138$

Step-by-step explanation:

a) The marginal cost function is given by the derivative of the total cost function, in this way the marginal cost function for this company is:

$\frac{dC(q)}{dq} = \frac{dC(q)}{dq} (0.000004q^ 3 - 0.03q ^ 2 + 100q + 75000) = 0.000012q^2 -0.06q + 100$

b) The income function is given by the relation $R (q) = P (q) q = -0.005q^2 + 200q$ .

The marginal revenue function for the company is given by the derivative of the revenue function, in this way the marginal revenue function is:

$\frac{dR(q)}{dq}= -0.01q+200$

(c) The profit function of the company is given by the relation $U (q) = R (q) - C (q)$ , and the marginal utility function is given by the derivative of the utility function, in this way , the marginal utility function is:

$\dfrac{dU(q)}{dq}=R'(q) - C'(q) = -0.01q+200 - (0.000012q^2-0.06q+100) = -0.000012q^2+0.05q+100$

When q = 2000, the marginal utility is:

$U'(2000)=-0.000012(2000)^2+0.05(2000)+100 = 152$

When q = 7000, the marginal utility is:

$U'(7000)=-0.000012(7000)^2+0.05(7000)+100 = -138$

6 0

4 years ago

A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum, we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = $\frac{x^{2} }{16}$

For the equilateral triangle, the length of the side = $\frac{23 - x}{3}$

Area = $\frac{\sqrt{3} }{4} a^{2} = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}$

Total Area = $\frac{x^{2} }{16}$ + $\frac{\sqrt{3} }{36} (23-x)^{2}$

$\frac{dA}{dx} = \frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x)\\$

$\frac{d^{2}A }{dx^{2} } = \frac{1}{8} + \frac{\sqrt{3} }{18} > 0$ , therefore it is minimum

$\frac{dA}{dx} = 0 \\\\$

$\frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x) = 0\\$

x = 10.00m

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3 years ago

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sleet_krkn [62]

Answer:

5.76

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2 years ago

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Vlad1618 [11]

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Answer:

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