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frez [133]
3 years ago
6

On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)

crosses the x-axis at (negative 4, 0) and crosses the y-axis at (0, negative 3).
Which statement is true about the graphed function?

F(x) < 0 over the interval (–∞, –4)
F(x) < 0 over the interval (–∞, –3)
F(x) > 0 over the interval (–∞, –3)
F(x) > 0 over the interval (–∞, –4)
Mathematics
2 answers:
laiz [17]3 years ago
5 0
10 hmmm i think is 10
murzikaleks [220]3 years ago
4 0
10 hmm ma
Bye yes lol yes
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What's 2/3 divided by 5
gtnhenbr [62]

Answer:2/15

Step-by-step explanation:

4 0
2 years ago
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I need help with this math problem
boyakko [2]
Consider the right triangle HBF. The Pythagorean theorem tells you ...
   HF² = HB² + BF²

The lengths HB and BF can be determined by counting grid squares, or by subtracting coordinates. Here, it is fairly convenient to count grid squares. When we do that, we find ...
   HB = 2
   BF = 5
Using these values in the equation above, we get
   HF² = 2² + 5²
   HF² = 4 + 25 = 29
Taking the square root gives the length HF.
   HF = √29

5 0
3 years ago
Margot is sewing a ribbon on a seam along the perimeter of a square pillow. The side length of the pillow is 2x2+1 inches. She p
polet [3.4K]
Infinity Many Solutions

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- Harvard university professor
8 0
3 years ago
Read 2 more answers
Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic
Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

df = n-1= 10-1=9

d.9

b) s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15

a.15

c) For this case we have the sample size n = 25 and the sample variance is s^2 =400 , the standard error can founded with this formula:

SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

df = n-1= 10-1=9

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

SS = \sum_{i=1}^n (X_i -\bar X)^2

And the sample variance for this case can be calculated from this formula:

s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is s^2 =400 , the standard error can founded with this formula:

SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80

8 0
3 years ago
I can’t figure this out at all.
Liula [17]
The fact that this triangle is a right angle triangle makes you now have 2 angles and the 1 side given, so it should be solvable.
First, You know that A=46 and C=90 as it is the right angle, and you know that the sum of any triangle's angles is 180. so now B=180-(90-46)=44
Now to the sides,
sin(B)=opp./hyp.=b/c=8/c=sin(44)
so, c=8/sin(44) which is approximately 11.52 unit length
now, use Pythagoras to find a,
a=√c²-b² =√11.52²-8² which is approximately 8.3 unit length.
Hope this helps.

6 0
3 years ago
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