Answer:
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Step-by-step explanation:




Sin(pi/4) = 1/sqrt(2)
csc(pi/4) = sqrt(2)
csc^2(pi/4) = 2
-csc^2(pi/4) = -2
Answer:
Mr. Garcia had 5 kilograms of blueberries at first
Step-by-step explanation:
to make this easiest, we can imagine that we're undoing mr. garcia's actions.
So, we can start by 'unpacking' mr garcia's bags
we know that each of the nine bags had 1/4 kilograms, so we can multiply 1/4 by 9 to find the collective mass packed into bags
(remember, multiplication is repeated addition. we could also add 1/4 + 1/4 + 1/4... nine times, but this would take a while)
so,
1/4 x 9 = 9/4
(9 = 9/1 [if that is how you're used to multiplying a fraction])
Then, he also sold 2 3/4 kilograms
so, we can add 2 3/4 + 9/4 to find the total mass of the blueberries at first
2 3/4 + 9/4 = 2 + 12/4
(12/4 = 3)
2 + 3 = 5
So, Mr. Garcia had 5 kilograms of blueberries at first
Answer:
the answer is c.
Step-by-step explanation: