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liraira [26]
3 years ago
12

Do oddsmakers believe that teams who play at home will have home field advantage? Specifically, do oddsmakers give higher point

spreads when the favored team plays home games as compared to when the favored team plays away games? Two samples were randomly
Mathematics
1 answer:
anygoal [31]3 years ago
8 0

Complete question is;

Do oddsmakers believe that teams who play at home will have home field advantage? Specifically, do oddsmakers give higher point spreads when the favored team plays home games as compared to when the favored team plays away games?

Two samples were randomly selected from three complete National Football League seasons (1989, 1990, and 1991). The first sample consisted of 50 games, where the favored team played in a home game, while the second sample consisted of 50 games, where the favored team played in an away game. The oddsmakers’ point spreads (which are the number of points by which the favored team is predicted to beat the weaker team) were then collected.

If µ1 and µ2 represent the mean point spread for home games and away games, respectively, which of the following is the appropriate.

A) H0: μ1 - μ2 = 0

Ha: μ1 - μ2 < 0

B) H0: μ1 - μ2 = 0

Ha: μ1 < μ2

C) H0: μ1 - μ2 > 0

Ha: μ1 - μ2 = 0

D) H0: μ1 - μ2 = 0

Ha: μ1 - μ2 > 0

E) None of the above

Answer:

D) H0: μ1 - μ2 = 0

Ha: μ1 - μ2 > 0

Step-by-step explanation:

We want to find out if oddsmakers give higher point spreads when the favored team plays home games as compared to when the favored team plays away games.

Now, since µ1 and µ2 represent the mean point spread for home games and away games, respectively;

It means we want to find out if µ1 > µ2 as the alternative hypothesis.

Thus, alternative hypothesis is;

Ha: µ1 - µ2 > 0

Meanwhile null hypothesis assumes that equal point spreads are given when the favored team plays home games as well as when the favored team plays away games.

Thus, null hypothesis is;

H0: μ1 - μ2 = 0

The only correct option is D.

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<u>Solution:</u>

Given that, Andy is buying a car.  

He negotiated a 7 percent decrease on a 6500 car.

Then, amount to be paid = 6500 – 7% of 6500  

\begin{array}{l}{\text { Amount to be paid }=6500 \times\left(1-\frac{7}{100}\right)} \\\\ {=6500 \times \frac{100-7}{100}=6500 \times \frac{93}{100}} \\\\ {\text { Amount to be paid }=65 \times 93=6045}\end{array}

He will pay the full balance in 12 equal monthly payments.

We have to calculate the amount paid each month

\begin{array}{l}{\text { monthly payment }=\frac{\text {total amount to be paid}}{12 \text { months }}} \\\\ {=\frac{6045}{12}=503.75}\end{array}

Hence, Andy has to pay £ 504 approximately each month.

5 0
3 years ago
A poll shows that 50% of students play sports. A random sample of 20 students showed that 70% of them play sports. A number gene
skelet666 [1.2K]

Answer:

Pr(≥ 70%) = 2/5 = 0.4

Step-by-step explanation:

This question is incomplete as we can't get an exact answer without the dot plot diagram.

We can tell from the question, we are to determine the probability of having ≥ 70% students that play sports

The dot plot diagram used in solving the question has been attached.

Total number of samples = 20

From the dot plot, 50% of students play sport. That is, 50% have more people playing sport than others.

The chance of getting a sample proportion of 70% or greater= probability of students that like sports ≥ 70%

= (sum of people that like sports ≥ 70%)/(total number of sample)

Pr(≥ 70%) = (4+3+1)/20

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Pr(≥ 70%) = 8/20

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3 years ago
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Step-by-step explanation:

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How do I solve this <br>​
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Answer:

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3 years ago
Solve the equation.<br> 3+ 4.5(2d – 3) = 7.5
Scorpion4ik [409]

Answer:

d=2

Step-by-step explanation:

Let's solve your equation step-by-step.

3+4.5(2d−3)=7.5

Step 1: Simplify both sides of the equation.

3+4.5(2d−3)=7.5

3+(4.5)(2d)+(4.5)(−3)=7.5(Distribute)

3+9d+−13.5=7.5

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9

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