All categories

3 years ago

What is a linear expression?

1 answer:

4 0

A linear expression is one that has a variable in it. Also, no variable is raised higher than a power of 1 or used as a denominator. So you can't divide by a variable. So if a linear equation is commonly expressed as "y= mx+b", a linear expression would be expressed as mx+b.

You might be interested in

(NEED HELP PLS HELP) i really need help

zalisa [80]

Answer:

the answer I believe is c

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is 2 1/4 ÷ 1/2=

marshall27 [118]

Answer:

Step-by-step explanation:

Convert mixed fraction to improper fraction.

$2\frac{1}{4}$ ÷ $\frac{1}{2}$ = $\frac{9}{4}$ ÷ $\frac{1}{2}$

Now use K C F method

K - Keep the first fraction

C - Change the division operation to multiplication

F- Flip the second number

$= \frac{9}{4} *\frac{2}{1}\\\\= \frac{9}{2}*1\\\\= \frac{9}{2}\\\\= 4 \frac{1}{2}$

4 0

2 years ago

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago

Help quick please, look at the photo I attached

Tema [17]

Answer:

A ≈ 5.6

Step-by-step explanation:

The area (A) of the triangle is calculated as

A = $\frac{1}{2}$ × PQ × PR × sin P

= 0.5 × 5.2 × 2.8 × sin50°

≈ 5.6 ( to 1 dec. place )

3 0

3 years ago

Flights arriving to DTW might be national or international. Assume that one out of every five national flights is followed by an

Dvinal [7]

Answer:

1/15

Step-by-step explanation:

Given

1 out of every 5 national flight is followed by an international flight.

p = 1/5

q = 1 - p

q = 1 - 1/5

q = 4/5

π0 = 0.25

We want to determine

p:the fraction of international flights that are followed by a national flight.

Let X = 0

If the nth flight is national

Let X = 1

if the flight is international

This gives rise to a two state Markov chain with transition probability as follows

P = (4/5. 1/5. p. 1-p)

The long run proportion are the below solution gotten from the Markov chain above

π0 = 4/5π0 + pπ1 ----- 1

π1 = 1/5π0 + (1 - p)π1---- 2

π0 + π1 = 1 -----------. 3

Solving the above equations,

We have

Substitute 0.25 for π0 in (3)

0.25 + π1 = 1

π1 = 1 - 0.25

π1 = 0.75

Solving 1 and 3

Substitute 0.75 for π1 and 0.25 for π0 in (1)

0.25 = 4/5 * 0.25 + 0.75p

0.25 = 0.2 + 0.75p

0.75p = 0.25 - 0.2

0.75p = 0.05

p = 0.05/0.75

P = 1/15 or 0.0667(6.67%)

So, one out of every 15 international flights is followed by a national flight (or 6.66 percent)

3 0

3 years ago

What is a linear expression?​

What is a linear expression?