Answer:
Step-by-step explanation:
less than I think
Answer:
Factored form is
f(x)= (x-1)(x-3+√(-5))(x-3-√(-5))
Step-by-step explanation:
Given that
f(x)=x3−7x2+2x+4
To solve for x we factorise the right side
f(x)=x3−7x2+2x+4
Let us substitute x for various values to check whether remainder is zero.
i.e. f(1) = 1-7+2+4 =0
Hence x-1 is a factor
Do synthetic division to find the quotient
1 1 -7 2 4
1 -6 -4
----------------------
1 -6 -4 0
i.e. we get remainder 0 and quotient as
x^2-6x-4
Use completion of squares method to solve this
x^2-6x-4
= (x-3)^2+5=0
x-3= ±√(-5)
Or x=1,3+√(-5,) 3-√(-5,)
Are the roots
Factored form is
f(x)= (x-1)(x-3+√(-5))(x-3-√(-5))
Answer:
C=50+20h
Step-by-step explanation:
Since 20 is going to be added every hour, that is the h value. Since 50 is the the initial payment, that is the other value
<u>Answer:</u>
The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is 
<u>Solution:</u>
Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.
We have to find the equation of the above polynomial.
We know that, general equation of 3rd degree polynomial is
where a, b, c are roots of the polynomial.
Here in our problem, a = 1, b = 2, c = -1.
Substitute the above values in f(x)
So, the equation is
Let us put x = 0 in f(x) to check whether our answer is correct or not.
Hence, the equation of the polynomial is
