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3 years ago

B. Write the number 800,000 + 6,000 + 300 + 2 in the place value chart.

Mathematics

1 answer:

Sveta_85 [38]3 years ago

3 0

Hundred thousands. 800,000

Ten thousands. 00,000

thousands. 6,000

Hundreds. 300

Tens 00

Ones. 2

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Express 1+√2/√2 in the form p+q√2

scoundrel [369]

$\frac{1+\sqrt{2}}{\sqrt{2}} = \frac{1}{\sqrt{2}} + \frac{\sqrt{2}}{\sqrt{2}} = 1 + \frac{1}{\sqrt{2}}$

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3 years ago

HELP ME PLEASE

yuradex [85]

Answer:

368 milliliters.

Step-by-step explanation:

Compound A + Compound B = 1 drug

4 + 7 = 1 drug

11 milliliters = 1 drug, so 1012 milliliters = 92 drugs

Multiply the compounds by the amount of drugs, e.g.

4 x 92 = 368 ( Compound A )

7 x 92 = 644 ( Compound B )

368 + 644 = 1012

368 milliliters of Compound A are needed to make 1012 milliliters of the drug.

Hope this helps :)

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3 years ago

A courier originally had 5 packages to deliver. Suppose x represents the number of packages she has delivered so far and y repre

Olenka [21]

Answer:

A,E,F

Step-by-step explanation:

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2 years ago

Please evaluate: (−2)^3 · (−2)^4<br> show your work

sammy [17]

Answer:

-128

Step-by-step explanation:

$(-2)^3 \cdot (-2)^4=$

$(-2\cdot -2\cdot -2) \cdot (-2\cdot -2\cdot -2\cdot -2)=$

$-8\cdot 16=$

$-128$

Hope this helps!

3 0

3 years ago

Read 2 more answers

Helpppp me please!!!

Semenov [28]

To find the value of q, we need to find d(-8). Put another way, we need to find the value of d(x) when x = -8

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(-8) = -\sqrt{\frac{1}{2}(-8)+4}$

$d(-8) = -\sqrt{-4+4}$

$d(-8) = -\sqrt{0}$

$d(-8) = 0$

So this means q = 0. Note that -0 is just 0.

===========================================

The value of r will be a similar, but now we use f(x) this time.

Plug in x = 0

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(0) = \sqrt{\frac{1}{2}*0+4}$

$f(0) = \sqrt{0+4}$

$f(0) = \sqrt{4}$

$f(0) = 2$

Therefore, r = 2.

===========================================

For s, we plug x = 10 into f(x)

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(10) = \sqrt{\frac{1}{2}*10+4}$

$f(10) = \sqrt{5+4}$

$f(10) = \sqrt{9}$

$f(10) = 3$

So s = 3.

===========================================

Finally, plug x = 10 into d(x) to find the value of t

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(10) = -\sqrt{\frac{1}{2}(10)+4}$

$d(10) = -\sqrt{5+4}$

$d(10) = -\sqrt{9}$

$d(10) = -3$

A shortcut you could have taken is to note how d(x) = -f(x), so this means

d(10) = -f(10) = -9 since f(10) = 9 was found in the previous section above.

Whichever method you use, you should find that t = -3.

===========================================

<h3>In summary:</h3><h3>q = 0</h3><h3>r = 2</h3><h3>s = 3</h3><h3>t = -3</h3>

8 0

3 years ago