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3 years ago

7

According to a certain central bank from 2000 to 2016 the average price of a new home in a certain region increased by %87 to

$ 572 thousand. What was the average price of a new home in 2000?

1 answer:

ch4aika [34]3 years ago

6 0

X*1.87= 572
X=572/1.87
X=$306

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Please i need an answer urgently. Sum of 3 terms are 252, first term is 192. Find common ratio

Viefleur [7K]

Answer:

$r=\frac{1}{4}\\\\r=-\frac{5}{4}$

Step-by-step explanation:

<u>Geometric Sequences</u>

The geometric sequence is given as:

$a_1, a_1r, a_1r^2, a_1r^3,..., a_1r^{n-1}$

Where n is the number of the term, n≥1, and r is the common ratio.

The sum of n terms of the geometric sequence is given by:

$\displaystyle S_n=a_1\frac{r^n-1}{r-1}$

We are given: S3=252, a1=192, thus substuting:

$\displaystyle 252=192\frac{r^3-1}{r-1}$

Dividing by 12:

$\displaystyle 21=16\frac{r^3-1}{r-1}$

Recall that:

$r^3-1=(r-1)(r^2+r+1)$

Substituting:

$\displaystyle 21=16\frac{(r-1)(r^2+r+1)}{r-1}$

Simplifying:

$21=16(r^2+r+1)=16r^2+16r+16$

Rearranging:

$16r^2+16r+16-21=0$

16r^2+16r-5=0

Rewriting:

$16r^2-4r+20r-5=0$

Factoring:

$4r(4r-1)+5(4r-1)=0$

$(4r-1)(4r+5)=0$

Solving:

$r=\frac{1}{4}\\\\r=-\frac{5}{4}$

Both solutions are valid

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3 years ago

Whats the slope of y - 7 = 3(x-1)

Ksenya-84 [330]

Answer:

slope is 3. m=3

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3 years ago

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The lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of

valina [46]

Answer:

(221.39, 300.61) and (255.2223, 266.7777)

Step-by-step explanation:

Given that X, the lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days

Middle 98% would lie on either side of the mean with probability ±2.33 in the std normal distribution on either side of 0

Corresponding we have x scores as

Between $261-2.33*17$ and $261+2.33*17$

i.e. in the interval = (221.39, 300.61)

If sample size = 47, then std error of sample would be

$\frac{17}{\sqrt{47} }$

So 98% of pregnancies would lie between

$261-2.33*\frac{17}{\sqrt{47} }$ and $262+2.33*\frac{17}{\sqrt{47} }$

= (255.2223, 266.7777)

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3 years ago

Light bulbs manufactured at a certain factory have a 3% probability of being defective. what is the probability that 5 out of a

lbvjy [14]

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. The probability that 5 out of a shipment of 30 will be defective is 0.001617.

<h3>What is Binomial distribution?</h3>

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. It is given by the formula,

P(x) = ⁿCₓ pˣ q⁽ⁿ⁻ˣ⁾

Where,

x is the number of successes needed,

n is the number of trials or sample size,

p is the probability of a single success, and

q is the probability of a single failure.

The probability of the bulb being defective is 3%(0.03) and the probability of the bulb not being defective is 97%(0.97).

Now, it is needed to be found that the probability that 5 out of a shipment of 30 will be defective can be written as,

P(x) = ⁿCₓ pˣ q⁽ⁿ⁻ˣ⁾

P(x=5) = ³⁰C₅ (0.03)⁵ (0.97)²⁵

P(x=5) = 0.001617

Hence, the probability that 5 out of a shipment of 30 will be defective is 0.001617.

Learn more about Binomial Distribution:

brainly.com/question/14565246

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2 years ago

Quizizz help 10 pts each brainiest guaranteed blah blah blah

emmainna [20.7K]

Answer:

$5x^3-2x^2+2x+9$

Step-by-step explanation:

(5x^3+4x^2)−(6x^2−2x−9)

To find the opposite of 6x^2−2x−9 find the opposite of each term.

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Combine 4x^2 and 6x^2 to get −2x^2.

5x^3-2x^2+2x+9

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3 years ago

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