All categories

2 years ago

Solve the following equation for y. Y= 2y+4y-3=27

Mathematics

1 answer:

sammy [17]2 years ago

4 0

Answer:

$2y + 4y - 3 = 27 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6y = 27 + 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6y = 30 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = \frac{30}{6} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = 5$

You might be interested in

In a survey 37% of people chose salads over a meat dish in all 81 people chose salads how many people were in the survey

Gelneren [198K]

Looks like the answer would be 219 people since you can't have half a person.

7 0

2 years ago

A telemarketer spent 7 hours during her 8-hour shift calling up new clients. What percentage of her time was spent on things oth

padilas [110]

1/8 of her time was spent on things other than working with clients. 1/8 = 0.125 * 100 = 12.5%

6 0

1 year ago

N+5/16=-1 Solve for n I will reward Brainliest

Wittaler [7]

Answer:

Step-by-step explanation:

−

n+\frac{5}{16}=-1

n+165=−1

Solve

Subtract

\frac{5}{16}

165

from both sides of the equation

−

n+\frac{5}{16}=-1

n+165=−1

−

n+\frac{5}{16}{\color{#c92786}{-\frac{5}{16}}}=-1{\color{#c92786}{-\frac{5}{16}}}

n+165−165=−1−165

Simplify

Solution

−

3 0

2 years ago

Which statement correctly identifies a point on the graph of f–1(x)?

Black_prince [1.1K]

Answer:

Step-by-step explanation:

I didn’t see any choices but an inverse function switches the x and y values.

For every (x,y) of f(x) the inverse function will have (y,x) of f^-1(x)

7 0

2 years ago

Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the

iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are $\frac{10\sqrt{2} }{3}$

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C = -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = $\frac{10\sqrt{2} }{3}$

From B = $\frac{10\sqrt{2} }{3}$

From C = $\frac{10\sqrt{2} }{3}$

7 0

2 years ago