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2 years ago

6

In Livingston the library is 8 miles due south of the courthouse and 15 miles due west of the community swimming pool what is th

e distance between the courthouse and the current community swimming pool

1 answer:

Charra [1.4K]2 years ago

4 0

Answer:

pic

Step-by-step explanation:

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Find the slope of the line passing through the given points

NNADVOKAT [17]

Answer:

-5/6

Step-by-step explanation:

Slope= y2-y1/x2-x1

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2 years ago

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A rectangle has a perimeter 60m and base21 m what is its area

Komok [63]

Since you're given the base for the perimeter of the rectangle, you can solve this question quickly.

First, you multiply 21 by 2, because there are two bases to a rectangle.

You'll get 42, and you will have to do 60-42 to find the perimeter for the remaining two sides.

60-42 will give you 18, so you can divide that by 2 because there are two other sides, giving you 9.

Now you have the side lengths 21 and 9. Area is base*height, so you can multiply 21*9 and get 189.

Therefore, the area of the rectangle is 189 meters

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3 years ago

Round 491,778 to the nearest hundred

hichkok12 [17]

Answer:

491,800!

Step-by-step explanation:

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2 years ago

Jones of Boston borrowed $40,000, 90 day, 10% note. After 60 days Jones made an initial payment of $6,000. Assuming the U.S. Rul

nadezda [96]

check a website called math-way without the dash it might help

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3 years ago

5. Find the discriminant of 15x2 = 4x – 1 and describe

diamong [38]

Answer:

a) The discriminant of the equation = - 44

b)The nature of the roots will be imaginary.

c) $x = \frac{2 +\sqrt{11} i}{15} or, x = \frac{2 - \sqrt{11} i}{15}$

Step-by-step explanation:

Here, the given expression is $15x^{2} = 4x -1$

or, $15x^{2} - 4x + 1 = 0$

Now the discriminant (D) of a quadratic equation $ax^{2} +b x + c = 0$

D = $b^{2} - 4ac = (-4)^{2} - 4(15) (1) = 16 - (60) = -44$

Hence, the discriminant of the equation = - 44

As D< 0, so the roots will be imaginary.

Now,by quadratic formula : $x = \frac{-b \pm \sqrt{b^{2} - 4ac} }{2a}$

So, here $x = \frac{-(-4) \pm \sqrt{D} }{2a} = \frac{4 \pm \sqrt{(-44 )} }{30}$

So, either $x = \frac{4 + \sqrt{(-44 )} }{30} or, x = \frac{4 - \sqrt{(-44 )} }{30}$

or, $x = \frac{2 +\sqrt{11} i}{15} or, x = \frac{2 - \sqrt{11} i}{15}$

8 0

2 years ago