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kolezko [41]
3 years ago
7

A triangle is rotated 90° about the origin. Which rule describes the transformation? (x, y) -(-x, -y) (x, y) - (-y, x) (x, y) -

(-4, -x) (x, y) (y, -x)​

Mathematics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

(x, y) arrow (-y, x)

Step-by-step explanation:

Therefore rule of counter is (x,y) arrow (-y,x) ...we have given a triangle is rotated 90'

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The sum of two numbers is 36. The first number is 1/5 of the second number. what are the numbers?
vfiekz [6]
Lets put this into an equation
x + 1/5 * x = 36
1.2x  = 36
x       = 30
1/5x = 6
So our final answer is 6 and 30.
Please mark me the Brainliest if I am correct.
7 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
which equation can replace 3x 5y = 59 in the original system and still produce the same solution? 2x – y = –4 10x – 5y = –20 7x
natka813 [3]
From my research, the original system of equations contain the following equations:

<span>2x − y = −4 
3x + 5y = 59

where obtained solution is x = 3

Among the choices, it is easier to substitute </span><span>3x + 5y = 59 with one of the choices to see if they yield the same solution set. From trial-and-error, the equation that can replace the original equation is " 13x = 39 ". Among the choices, it is the 4th choice.</span>
8 0
3 years ago
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Find the sum (a-b)(2a+4b)
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The perpendicular bisectors.

6 0
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