Answer:
u can be using it at perpendicular and place it's center on point A
hope that helps a bit-
Answer:
-4i = 4(cos 270 +i sin 270)
Step-by-step explanation:
We have a+ib = r(cosθ+isinθ)
Here a = 0 and b = -4
Substituting
-4i = 4(cos 270 +i sin 270)
The most consistent attendance is the one that has less variability (it's more regular). Not necessarily the one with more students. So, the case with less variability is the one with less IQ, sigma or range (all three measure the dispersion of a distribution. IQ is more robust than sigma, and sigma more than the range, although in practice everyone uses sigma).
So, the answer to A) is the third High School: HS P
B) Here one looks at the central measurement: mean, median. This example is not super easy. HS N has the highest mean value, but HS P has the highest median. The median is more robust than the mean, since it is less affected by outliers. So HS P is a good candidate.
Finally, looking at the Low/High values, one can see that the high is the same: some day(s) when all students went and all HS have a maximum number of 180 students. However, the highest low is HS P.
So, I think HS P should also be awarded for the highest rate, since its median
is the highest and the lower number of students is the highest.
Median means 50% of the cases have values less than the median. Mean is an average.
Answer:
<h2>m∠LMN = 26°</h2>
Step-by-step explanation:
Since ∠LMN and ∠PQR are complementary it means that the sum of their angles is 90°
To find m∠LMN , add both m∠LMN and m∠PQR and equate it to 90 to find x then substitute the value of x into the expression for m∠LMN
That's
m∠LMN + m∠PQR = 90
4x - 2 + 9x + 1 = 90
13x - 1 = 90
13x = 90 + 1
13x = 91
Divide both sides by 13
x = 7
From the question
m∠LMN = (4x-2)
m∠LMN = 4(7) - 2 = 28 - 2
We have the final answer as
<h3>m∠LMN = 26°</h3>
Hope this helps you
