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3 years ago

I know im asking a lot of questions but i really need your help

Mathematics

2 answers:

ElenaW [278]3 years ago

8 0

Erm I don’t see anything here

lions [1.4K]3 years ago

3 0

Answer:

Erm i dont see anything here.

Step-by-step explanation:

You might be interested in

What is the formula for the nth term for the following sequence? 12, 9, 6, 3, ...

Lady bird [3.3K]

Answer:

your questions answer is 37.

4 0

3 years ago

First use front end rounding to estimate the answer. Then multiply to find the exact answer.

iren2701 [21]

Answer:

Estimated answer = 57.0

Exact answer = 54.04

Step-by-step explanation:

Since 19.3 is lesser than 19.5, it will be rounded down to 19.0

Since 2.8 is greater than 2.5, it will be rounded up to 3.0

Estimated multiplication

19.0 * 3.0 = 57.0

Actual multiplication

19.3 * 2.8 = 54.04

4 0

3 years ago

Read 2 more answers

PLZ HELP! dont just answer something random for points:)tysm

sergiy2304 [10]

Answer:

$4(x^{2} -4)^{2} -76$

Step-by-step explanation:

Take out 4:

4(x^2-8x)-12

=4(x^2-8x+16-16)-12

=4(x^2-8x+16)-64-12

=4(x^2-4)^2 - 76

= $4(x^{2} -4)^{2} -76$

6 0

3 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

Mr. Shamir employs two part-time typists, Inna and Jim, for his typing needs. Inna charges $15 an hour and can type 6 pages an h

coldgirl [10]

Answer:

The minimum cost would be 480$ when Inna works for 8 hours and Jim works for 20 hours.

Step-by-step explanation:

We are given the following information in the question:

Charges for 1 hour for Inna = $15

Number of pages typed by Inna in 1 hour = 6

Charges for 1 hour for Jim = $18

Number of pages typed by Jim in 1 hour = 8

Let x be the number of hours Inna work and let y be the number of hours Jim work.

Total cost = $15x + 18y$

We have to minimize this cost.

Then, we can write the following inequalities:

$6x + 8y \geq 208\\x \geq 8\\y \geq 8\\$

The corner points as evaluated from graph are: (8,20) and (24,8)

C(8,20) = 480$

C(24,8) = 504$

Hence, the minimum cost would be 480$ when Inna works for 8 hours and Jim works for 20 hours.

The attached image shows the graph.

3 0

3 years ago