We have q
consecutive integers in a set and q is odd.
If 120 is the middle number, then
there will be (q-1)/2 numbers
both before
and after 120.
Therefore, the largest number will
be (q-1)/2+120.
1/5÷2
=1/5·1/2
=1/10
Or you can say 0.1.
That's your answer.
Answer:
24 ( 12 -3x)
Step-by-step explanation:
(4x3 + 7x2 – 2) (2x2 – 3x + 8)
(12 + 14 - 2) (4 - 3x + 8)
(26-2) (12 - 3x)
24 (12 -3x)
Answer:
46, 57 , 67
Step-by-step explanation:
Acute scalene triangle : A triangle in which all three angles are less then 90 degrees and all three angles are different measurements .
have a good day
let 2nd angle = x
then 1st angle = 2x-15
then you have 90 = x + 2x-15
2x +x = 3x
so now 90 = 3x-15
add 15 to each side
105=3x
x = 105/3 = 35
1st angle = 35 degrees
2nd angle = 2(35) - 15 = 70-15 = 65
