Would love some help

Mathematics

1 answer:

natali 33 [55]3 years ago

7 0

<h3>Answer: 90 cubic meters</h3>

Each triangle has a base of 10 and height of 3.6

area of triangle = 0.5*base*height = 0.5*10*3.6 = 18 square meters

multiply this with the height of the prism (5 meters) to get 18*5 = 90 cubic meters. I'm using the idea that,

volume of prism = (area of base face)*(height of prism)

The notation "m^3" is shorthand for "cubic meters"

We do not use the other dimensions of 9 m and 7 m.

You might be interested in

the Cross Country Coach Les Sherman set the length of the football field is 120 yards. All the students must run five laps. Usin

Irina18 [472]

120 divided by 6 = 20

8 0

3 years ago

Which relationship would most likely have a positive correlation?

tiny-mole [99]

Answer:

Step-by-step explanation:

The only thing to do here is just check all of the answers.

A makes no sense, as the number of keys on a keyboard doesn't affect the amount of memory in a computer at all (no correlation).

B makes a bit more sense, but it's still wrong. If a train travels faster, it gets places quicker, or the time goes down. If (If one goes up, the other goes down) is true, then you have negative correlation.

C makes the most sense, as if there's more people at a game, then those more people will probably buy more hot dogs. If (If one goes up, so does the other) is true, then you have positive correlation, which is what we want.

4 0

3 years ago

Why does it make sense to use 660 and 60 to estimate the quotient

Alexxx [7]

What the qoutient sweetheart

5 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$