I think the it would be some like y-8
Answer: The required equation is
and the number of fishes in the pond on June 1 = 115
Step-by-step explanation:
Given: The number of fishes in pond on July 1 = 63
Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.
Let f be the number of fishes in pounds on June 1.
then the required equation will be

Now, add 52 on both the sides of the equation, we get

V(s) = (S)^3
6 cube shapes with sides ranging in whole numbers from 2 feet to 7 feet:
S1 = 2 feet, S2 = 3 feet, S3 = 4 feet, S4 = 5 feet, S5 = 6 feet, S6 = 7 feet
V(s)1 = (S1)^3 = (2)^3 = 8 cubic feet
V(s)2 = (S2)^3 = (3)^3 = 27 cubic feet
V(s)3 = (S3)^3 = (4)^3 = 64 cubic feet
V(s)4 = (S4)^3 = (5)^3 = 125 cubic feet
V(s)5 = (S5)^3 = (6)^3 = 216 cubic feet
V(s)6 = (S6)^3 = (7)^3 = 343 cubic feet
I think you may have forgotten to give the rest of the question