He is 2√19 miles far way from starting point.
Suppose Billy starts at point A, turns at point B, and ends at point D, as shown below.
If Billy turns 60◦ northward and walks six miles, then we can draw a 30 − 60 − 90 triangle whose hypotenuse is 6 miles
It follows that Billy traveled 6/2 = 3 miles eastward during these 6 miles, and that he traveled 3√3 miles northward during these 6 miles. In total, Billy traveled 4 + 3 = 7 miles eastward and 3√ 3 miles northward.
By the Pythagorean Theorem, the distance from his starting point is q:
(7)2 + (3√3)2
=√49 + 27
= √76
= 2√19 .
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Answer:
C. (2, 1)
Step-by-step explanation:
-3y = x-5
x+ 5y = 7
Subtract x from both sides in the first equation. Write the second equation below it.
-x - 3y = -5
x + 5y = 7
Add the two equations above.
2y = 2
Divide both sides by 2.
y = 1
Substitute y with 1 in the second original equation and solve for x.
x + 5(1) = 7
x + 5 = 7
Subtract 5 from both sides.
x = 2
Answer: C. (2, 1)
First, u do -9+8x-4+8
Then, U simplify. The answer is 8x-5
I would assume that he's using a 90° rotation.
4.a)2x+10 >27
4.b) 27-10= 17
17/2=8.5
3.a) 40-2x>7
3.b) 7-40=-33
-33/-2=16.5
So 16 students in her class