Area=length*width
(32+48)=(16)*(width)
80=(16)(width)
width=(80/16)
5=width
Option C is the right answer
½(12) = 6
½(64) = 32
½(30) = 15
½(78) = 39
Answer:
18 combinations
Step-by-step explanation:
There are three chocolates and six different options to mix with those chocolates. Each chocolate has six different options. So, it comes to 6 + 6 + 6 or 6 • 3 whoch equals 18 different combinations.
5 is common factor
also x
reverse distributive
ab+ac=a(b+c)
5x(x)+5x(4)=5x(x+4)
last one
Answer:
(-4, -8)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
x - 2y = 12
5x + 3y = -44
<u>Step 2: Rewrite Systems</u>
x - 2y = 12
- [Multiplication Property of Equality] Multiply everything by -5: -5x + 10y = -60
<u>Step 3: Redefine Systems</u>
-5x + 10y = -60
5x + 3y = -44
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Elimination</em>
- Combine 2 equations: 13y = -104
- [Division Property of Equality] Divide 13 on both sides: y = -8
<u>Step 5: Solve for </u><em><u>x</u></em>
- Define original equation: x - 2y = 12
- Substitute in <em>y</em>: x - 2(-8) = 12
- Multiply: x + 16 = 12
- [Subtraction Property of Equality] Subtract 16 on both sides: x = -4
