Split up each force into horizontal and vertical components.
• 300 N at N30°E :
(300 N) (cos(30°) i + sin(30°) j)
• 400 N at N60°E :
(400 N) (cos(60°) i + sin(60°) j)
• 500 N at N80°E :
(500 N) (cos(80°) i + sin(80°) j)
The resultant force is the sum of these forces,
∑ F = (300 cos(30°) + 400 cos(60°) + 500 cos(80°)) i
… … … + (300 sin(30°) + 400 sin(60°) + 500 sin(80°)) j N
∑ F ≈ (546.632 i + 988.814 j) N
so ∑ F has a magnitude of approximately 1129.85 N and points in the direction of approximately N61.0655°E.
Answer:
E , G, B
Step-by-step explanation:
I did it
Answer:
5.66 units.
Step-by-step explanation:
cos 25 =- adjacent side / hypotenuse
cos 25 = 4 / AB
AB cos 45 = 4
AB = 4 / cos 45
= 5.66.
Here you go! Hopefully it was correct as i used an app called Cymath.Please mark me as Brainliest!
Answer:
Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.
Step-by-step explanation:
Given the inequality function
0.7S+0.5L≤11 where S represent the number of sunflower plants and L represent the number of lily plants Ezra's water supply can water, if Ezra waters 10 lily plants, then we can calculate the maximum amount of sunflower plant that he can water with the remaining amount of water by simply substituting L = 10 into the inequality function as shown;
0.7S+0.5L≤11
0.7S+0.5(10)≤11
0.7S+5≤11
Taking 5 to the other side:
0.7S≤11-5
0.7S≤6
S≤6/0.7
S≤8.57
This shows that Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.
