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Sedaia [141]
3 years ago
11

What is 23/8 as a decimal?

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0
To write 23/8 as a decimal you have to divide numerator by the denominator of the fraction. 
<span>We divide now 23 by 8 what we write down as 23/8 and we get 2.875 </span>

<span>And finally we have: </span>
23/8 as a decimal<span> equals </span><span>2.875</span>
Alisiya [41]3 years ago
4 0
Hello there! 

In order to "convert" a 'fraction' to a decimal you'll need to divide  the numerator from the denominator

So, 23 ÷ 8 equals 2.875

So,  therefore \frac{23}{8} as a decimal would be 2.875

Good luck on your assignment and enjoy your day! 

                                     ~MeIsKaitlyn:)
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Elena randomly chooses a number from 1 to 10. What is the probability she chooses a number greater than 5?
zepelin [54]

ANSWER

P(E)=\frac{1}{2}

EXPLANATION

From the given information, Elena chooses a number from 1 to 10.

The sample space is

S={1,2,3,4,5,6,7,8,9,10}

n(S)=10

The numbers greater than 5 are:

E={6,7,8,9,10}

n(E)=5

The probability that, she chooses a number greater than 5 is:

P(E) =  \frac{n(E)}{n(S)}

Substitute the values,

P(E) =  \frac{5}{10}

P(E) =  \frac{1}{2}

5 0
3 years ago
Luis rides his bicycle 34 mile in 5 minutes, or 112 hour, along the bike trail. Assuming he rides at a constant rate, what is hi
artcher [175]

Answer:

408\frac{miles}{hour}

Step-by-step explanation:

we know that

To find the speed divide the total distance by the time

so

\frac{34}{(1/12)}=34*12=408\frac{miles}{hour}

3 0
3 years ago
Round .859 to nearest tenth
Nikolay [14]
0.9. The reason why is because the 5 brings the 8 to a 9.
6 0
3 years ago
Read 2 more answers
The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is
saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

   α = 0.05, α/2 = 0.025

  From the t tables, T.INV.2T(α, degree of freedom), we find the t value as

  t =T.INV.2T(0.05, 128) = 2.34

  Taking the positive value of t, we get  

  Confidence interval is ,

  $\overline X \pm t \times \frac{s}{\sqrt n}$

 $34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$

 (32.52, 35.8)

 95% confidence interval is  (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.  

4 0
3 years ago
Y=-4x-10 for all prime numbers less than 15. What is the domain and range for this?
Bad White [126]
The\ prime\ numbers\ less\ than\ 15\ is\ domain:\\\\D=\{2;\ 3;\ 5;\ 7;\ 11;\ 13\}\\\\Range:\\\\f(2)=-4(2)-10=-18\\f(3)=-4(3)-10=-22\\f(5)=-4(5)-10=-30\\f(7)=-4(7)-10=-38\\f(11)=-4(11)-10=-54\\f(13)=-4(13)-10=-62\\\\Range:\{-18;-22;-30;-38;-54;-62\}
4 0
3 years ago
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