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Sedaia [141]
3 years ago
11

What is 23/8 as a decimal?

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0
To write 23/8 as a decimal you have to divide numerator by the denominator of the fraction. 
<span>We divide now 23 by 8 what we write down as 23/8 and we get 2.875 </span>

<span>And finally we have: </span>
23/8 as a decimal<span> equals </span><span>2.875</span>
Alisiya [41]3 years ago
4 0
Hello there! 

In order to "convert" a 'fraction' to a decimal you'll need to divide  the numerator from the denominator

So, 23 ÷ 8 equals 2.875

So,  therefore \frac{23}{8} as a decimal would be 2.875

Good luck on your assignment and enjoy your day! 

                                     ~MeIsKaitlyn:)
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Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
3 years ago
Please help me this is urgent.!
nata0808 [166]
V= 3.14• 5^2•4
V= 3.14 •25•4
V= 78.5•4
V=314

Sorry I couldn’t give a more detailed explanation but here is the original equation for volume of a cylinder:

V=πr2h

Hope this helps comment below for more questions :)
3 0
3 years ago
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