The Confidence interval for 95% who believes that the local businesses overcharge = (0.7026, 0.7574)
<h3>
What is meant by confidence interval?</h3>
The range of values we see in our sample and hope to identify the value that most closely represents the population are referred to as a confidence interval.
<h3>According to the given information:</h3>
Sample size n = 1000
73% of town residents believed that local businesses overcharged for their products over 1000 resident.
= (1000/100) x 73
= 730
Sample proportion p = 730/1000
= .73
q = 1-p = 0.23
Std error of proportion = √(pq/n)
= √((.73*0.27)/1000)
= 0.0140
95% Z critical value = 1.96
Margin of error = 1.96*0.0140
= 0.0274
Confidence interval = sample proportion ±margin of error
(0.7026, 0.7574)
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To me it seems like 10ft 1 min if u do simple math
Number of feet in a mile multiplied by the percentage (7/11) equals number of feet in the 7/11 portion of a mile.
=5280 * 7/11
=(5280*7)/11
=36,960/11
=3,360 feet in 7/11 mile
Hope this helps! :)
Answer:
d
Step-by-step explanation:
