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Igoryamba
3 years ago
12

Find the surface area of each figure (spheres and hemispheres)

Mathematics
1 answer:
xenn [34]3 years ago
8 0

Answer:

7. 1520.53 cm²

8. 232.35 ft²

9. 706.86 m²

10. 4,156.32 mm²

11. 780.46 m²

12. 1,847.25 mi²

Step-by-step explanation:

Recall:

Surface area of sphere = 4πr²

Surface area of hemisphere = 2πr² + πr²

7. r = 11 cm

Plug in the value into the appropriate formula

Surface area of the sphere = 4*π*11² = 1520.53 cm² (nearest tenth)

8. r = ½(8.6) = 4.3 ft

Plug in the value into the appropriate formula

Surface area of the sphere = 4*π*4.3² = 232.35 ft² (nearest tenth)

9. r = ½(15) = 7.5 m

Surface area of the sphere = 4*π*7.5² = 706.86 m² (nearest tenth)

10. r = ½(42) = 21 mm

Plug in the value into the formula

Surface area of hemisphere = 2*π*21² + π*21² = 2,770.88 + 1,385.44

= 4,156.32 mm²

11. r = 9.1 m

Plug in the value into the formula

Surface area of hemisphere = 2*π*9.1² + π*9.1² = 520.31 + 260.15

= 780.46 m²

12. r = 14 mi

Plug in the value into the formula

Surface area of hemisphere = 2*π*14² + π*14² = 1,231.50 + 615.75

= 1,847.25 mi²

You might be interested in
A³b² a²b simplify the following expression
liberstina [14]

Answer:

a^{5}b^{3}

Step-by-step explanation:

The law of indices can be used to simplify mathematical expressions involving  arithmetical operation on variables with powers.

a^{m} x a^{n} = a^{(m+n)}

Thus, the given expression can be simplified as follows:

a³b² a²b  = a³ x a² x b² x b^{1}

               = a^{3+2} x b^{2+1}

               = a^{5}b^{3}

Thus,

a³b² a²b  = a^{5}b^{3}

7 0
2 years ago
The volume of a pyramid varies jointly as the height and the area of the base. If a pyramid has the measurements V=1144
Naddika [18.5K]

Answer:

  • 11040 m³
  • k ≈ 0.33
  • V = (1/3)Bh

Step-by-step explanation:

The given relation is ...

  V = kBh . . . . . for some base area B, height h, and constant of variation k

We are given length and width of the base so we presume it is a rectangle.

  B = l·w = 8·11 = 88 . . . . square meters

The given volume tells us the value of k:

  1144 = k(88)(39) . . . . . . cubic meters

  1144/3432 = k = 1/3 ≈ 0.33

The value of k is about 0.33.

__

Then the volume of the larger pyramid is ...

  V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³

The general relationship is ...

  V = 1/3Bh

7 0
3 years ago
I need help. this is due in less than 10 min and i have no clue how to solve. any tips appreciated
babymother [125]

Answers:

  • a) x = 9
  • b) arc JK = 68
  • c) arc MJ = 112
  • d) arc LMK = 248

================================

Explanation:

Arcs JK and KL form a semicircle, so they add to 180 degrees

(arcJK) + (arcKL) = 180

(5x+23) + (17x-41) = 180

22x-18 = 180

22x = 180+18

22x = 198

x = 198/22

x = 9

Then you'll use this x value to find arc JK and arc KL

arc JK = 5x+23 = 5*9+23 = 68

arc KL = 17x - 41 = 17*9-41 = 112

Since central angles MNJ and KNL are vertical angles, this means minor arcs MJ and KL are congruent arcs. So arc MJ is also 112 degrees

Arc LMK is basically nearly everything of the full circle, but we exclude out the portion from L to K (the shorter distance)

arc LMK = (full circle) - (measure of minor arc LK)

arc LMK = 360 - 112

arc LMK = 248

8 0
3 years ago
A circle has a circumference of 46 meters. What is<br> the radius of the circle?
lara [203]
It’s rather half of that or double of that
6 0
2 years ago
Match the medication with its food recommendation
Ann [662]

Answer:

we need more information then that....

Step-by-step explanation:

6 0
3 years ago
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