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Nataly [62]
3 years ago
9

Help me please for this question im heavily confused.

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

a)

Let x = number of candy bars sold

Let y = amount of money earned

b)

y = 0.75x

c)

He should work at the car wash.

Step-by-step explanation:

a)

Let x = number of candy bars sold

Let y = amount of money earned

b)

$42.75/57 = $0.75

Each candy bar costs $0.75

We can confirm that by dividing $38.25/51 = $0.75

1 candy bar sells for $0.75

2 candy bars sell for $0.75 * 2

x candy bars sell for 0.75 * x, or simply 0.75x

The equation is y = 0.75x

c)

y = 0.75x

y = 0.75 * 36

y = 27

Larry raised $27 by selling candy bars last year. This year, he can earn more than that by working at the car wash.

He should work at the car wash.

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Y = -3x - 2 and 5x + 2y = 15
denis-greek [22]

Answer:

(-19, 55)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -3x - 2

5x + 2y = 15

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                     5x + 2(-3x - 2) = 15
  2. Distribute 2:                          5x - 6x - 4 = 15
  3. Combine like terms:            -x - 4 = 15
  4. Isolate <em>x</em> term:                      -x = 19
  5. Isolate <em>x</em>:                               x = -19

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    y = -3x - 2
  2. Substitute in <em>x</em>:                                     y = -3(-19) - 2
  3. Multiply:                                                y = 57 - 2
  4. Subtract:                                               y = 55
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3 years ago
Solve for x in the equation:log6-2logx=1.4​
Annette [7]

9514 1404 393

Answer:

  x = (√6)/10^0.7 ≈ 0.488737

Step-by-step explanation:

It can work reasonably well to take antilogs first.

  \log(6)-2\log(x)=1.4\\\\\dfrac{6}{x^2}=10^{1.4}\\\\\dfrac{6}{10^{1.4}}=x^2\\\\x=\dfrac{\sqrt{6}}{10^{0.7}}\approx0.488737

7 0
3 years ago
I need help please someone help
schepotkina [342]

Answer:

It's the second box.

Step-by-step explanation:

There, you are getting the most product for the cheapest.

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