Please help, will give brainliest for correct answer

If the first 4 terms of an infinite geometric sequence are 150, 120, 96, and 76.8, then the sum of all the terms in the sequence

hammer [34]

The sum of the sequence is 750

<h3>How to determine the sum of the series?</h3>

The series is given as:

150, 120, 96, and 76.8,

Start by calculating the common ratio using:

r = T2/T1

This gives

r = 120/150

r = 0.8

The sum of the series is then calculated as:

$S = \frac{a}{1 - r}$

This gives

$S = \frac{150}{1 - 0.8}$

Evaluate

S = 750

Hence, the sum of the sequence is 750

Read more about sequence at:

brainly.com/question/6561461

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4 0

2 years ago

Evaluate Jessica’s work and Sally’s review to determine which statement is true. Jessica did not solve for the correct value of

olya-2409 [2.1K]

Answer:

Step-by-step explanation: c I took it

7 0

3 years ago

Read 2 more answers

Someoneee pleaseee helppp!!!!

Andreas93 [3]

Answer:

Step-by-step explanation:

Angles 3, 4, and 5 are supplementary to each other, meaning that all of them added together equal 180. Therefore, to solve for x:

x + 18 + x + 15 + 4x + 3 = 180 and

6x + 36 = 180 and

6x = 144 so

x = 24

Angles 1 and 3 are vertical angles, so they are congruent, meaning they both have the exact same angle measure. If angle 3 measures, x + 18, so does angle 1. If x = 24, then angle 1 = 24 + 18 which is 42 degrees.

That also answered part c. Angles 1 and 3 are not complementary, they are vertical.

3 0

3 years ago

William purchased 76.9 feet of fencing for his back yard. He realized after measuring, that he still needed an additional 25.7 f

Lostsunrise [7]

William needs 102.6 fencing in all because 76.9 plus 25.7 equals 102.6, hope this helps!

3 0

3 years ago

In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

So

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0

3 years ago