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BartSMP [9]
3 years ago
10

Help with question, best answer gets brainliest

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

I think B

Step-by-step explanation:

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Bond [772]

Answer:47

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3 years ago
Help! I need the answers quick please
Norma-Jean [14]

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Step-by-step explanation:

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3 years ago
I NEED HELP WITH THIS PLEASEEE!!!!!
Galina-37 [17]
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The area for the square on the left is 81m^2. This is found because all sides of this square are the same, so the length and width are the same. Just multiply 9 x 9.

The area for the triangle is 31.5m^2. We find the left side is 9 meters because the triangle shares the same side as the square on the left side. We also find the bottom side is 7 because that is the length of each side of that square because all sides on a square is the same. We then multiply 9 times 7, getting 63, we divide this by 2 because it’s a triangle.

The square on the right has the area of 225 because both length and width is 15.

4 0
3 years ago
WILL GIVE 100 POINTS AND BRAINLIEST FOR BEST ANSWER
coldgirl [10]

Answer:

Step-by-step explanation:-16x^2 + 24x + 16 = 0.

A. Divide by 8:

-2x^2 + 3x + 2 = 0, A*C = -2*2 = -4 = -1 * 4. Sum = -1 + 4 = 3 = B, -2x^2 + (-x+4x) + 2 = 0,

(-2x^2-x) + (4x+2) = 0,

-x(2x+1) + 2(2x+1) = 0,

(2x+1)(-x+2) = 0, 2x+1 = 0, X = -1/2. -x+2 = 0, X = 2.

X-intercepts: (-1/2,0), (2,0).

B. Since the coefficient of x^2 is negative, the parabola opens downward. Therefore, the vertex is a maximum.

Locate the vertex: h = Xv = -B/2A = -24/-32 = 3/4, Plug 3/4 into the given Eq to find k(Yv). K = -16(3/4)^2 + 16(3/4) + 16 = 19. V(h,k) = V(3/4,19).

C. Choose 3 points above and below the vertex for graphing. Include the points calculated in part A which shows where the graph crosses the x-axis.

4 0
3 years ago
Plot the corresponding points for the inverse of the function represented by this table of values. x -4 0 3 7
NNADVOKAT [17]

Answer:

See explanation

Step-by-step explanation:

Given the function f(x) for which

\begin{array}{ccccc}x&-4&0&3&7\\ \\f(x)&9&5&2&-2\end {array}

If you want to plot the corresponding points for the inverse of the function f(x), change f(x) into y:  

\begin{array}{ccccc}x&-4&0&3&7\\ \\y&9&5&2&-2\end {array}

switch x and y

\begin{array}{ccccc}y&-4&0&3&7\\ \\x&9&5&2&-2\end {array}

and then change y into f^{-1}(x).

You get

\begin{array}{ccccc}x&9&5&2&-2\\ \\f^{-1}(x)&-4&0&3&7\end {array}

Now plot these points on the coordinate plane (see attached diagram).

3 0
3 years ago
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