Answer:
a) h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
b) 2.92
Step-by-step explanation:
a)
Here
Number of interviewees = N = 12
Number of job openings = M = 5
Interviews schedules for the first day = n = 7
N − M = 12 - 5 = 7
Using hypergeometric distribution:
Let X be the no. top four candidates interviewed on first day.
The probability mass function of X:
P(X = x) =
/ 
It can be written as:
h(x; n, M, N) =
/
= (5Cx) (7C7-x) / (12C7)
= (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
b)
The expectation is: E(X) = np
E(X) = n * M/N
= 7 * 5/12
= 7 * 0.41667
= 2.9167
Answer:
it is 6240
Step-by-step explanation:
you are so welcome
Answer:
(7x^2 -1)(x - 2).
Step-by-step explanation:
7x^3 - 14x^2 - x + 2
We can factor this by grouping - that is factoring the first 2 terms and the last 2:
= 7x^2(x - 2) - 1(x - 2) <-- the x - 2 is common to both parts so we have:
(7x^2 -1)(x - 2).
Answer:
F is 1/10
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
starts with 4 and is multiplied by 3 every term