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Vesnalui [34]
3 years ago
6

Plot the corresponding points for the inverse of the function represented by this table of values. x -4 0 3 7

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

Given the function f(x) for which

\begin{array}{ccccc}x&-4&0&3&7\\ \\f(x)&9&5&2&-2\end {array}

If you want to plot the corresponding points for the inverse of the function f(x), change f(x) into y:  

\begin{array}{ccccc}x&-4&0&3&7\\ \\y&9&5&2&-2\end {array}

switch x and y

\begin{array}{ccccc}y&-4&0&3&7\\ \\x&9&5&2&-2\end {array}

and then change y into f^{-1}(x).

You get

\begin{array}{ccccc}x&9&5&2&-2\\ \\f^{-1}(x)&-4&0&3&7\end {array}

Now plot these points on the coordinate plane (see attached diagram).

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In the diagram shown of circle A, tangent MB is drawn along with chords BAC and BF . Secant MFE intersects BAC at G. It is known
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  • arc BF = 76°
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Step-by-step explanation:

(a) ∠FBM is the complement of ∠FBC, so is ...

  ∠FBM = 90° -52° = 38°

The measure of arc BF is twice this angle, so is ...

  arc BF = 2∠FBM = 2(38°)

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(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...

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__

(c) arc FC is the supplement to arc BF, so has measure ...

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∠BGE is half the sum of arcs BE and FC, so is ...

  ∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2

  ∠BGE = 121°

__

(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...

  ∠MFB = 180° -∠M -∠FBM = 180° -31° -38°

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