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Lilit [14]
3 years ago
12

Value of x Can you help out again

Mathematics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

right angle I dont really no sorry

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Need help on this question can someone help please and thank you!
Eva8 [605]

Answer:

Jesse is correct because -5<-2

Step-by-step explanation:

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6 0
3 years ago
Value of x in log5x = 4logx5 is
olchik [2.2K]
Log5 x=4 logx 5
Ln x/ln5=4(ln5 / ln x)                                 logx z=ln x / ln z
least common multiple=ln5 * ln x

ln²x=4ln²5
√(ln² x)=√(4 ln²5)
ln x=2ln 5
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Answer: x=25.

4 0
3 years ago
How to show these 2 problems are inverses
nataly862011 [7]
\bf \begin{cases}&#10;f(x)=\sqrt[3]{7x-2}\\\\&#10;g(x)=\cfrac{x^3+2}{7}&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;now&#10;\\\\&#10;f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}&#10;\\\\\\&#10;\sqrt[3]{x^3}\implies x\\\\&#10;-----------------------------\\\\&#10;or&#10;\\\\&#10;g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}&#10;\\\\\\&#10;\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
8 0
3 years ago
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