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Degger [83]
3 years ago
8

Value of x in log5x = 4logx5 is

Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0
Log5 x=4 logx 5
Ln x/ln5=4(ln5 / ln x)                                 logx z=ln x / ln z
least common multiple=ln5 * ln x

ln²x=4ln²5
√(ln² x)=√(4 ln²5)
ln x=2ln 5
x=e^2ln5=25

Answer: x=25.

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Prove that f(x)=x+3/2 and g(x)=2x-3are inverse
goldfiish [28.3K]

Answer:

Proofs

Step-by-step explanation:

f(x) = x +  \frac{3}{2}

y = x +  \frac{3}{2}

x = y +  \frac{3}{2}

x -  \frac{3}{2}  = y

{f}^{ - 1} (x) = x -  \frac{3}{2}

They are not inverse because f^-1(x) = x - 3/2 is not the inverse to g(x) = 2x - 3.

5 0
3 years ago
Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into t
almond37 [142]
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3 0
3 years ago
Use mathematical induction to prove that if L is a linear transformation from V to W, then L (α1v1 + α2v2 +· · ·+αnvn)= α1L (v1)
e-lub [12.9K]

Answer:

The proof is shown in the explanation below.

Step-by-step explanation:

Analysis:

The proof by induction focuses on n. In this case, let n = 1, and L^{1} will be a linear operator since L^{1} = L

The exercise will show that L^{n} is a linear operator on V and that L^{n+1} is also a linear operator on V. This, follows that:

L^{n+1} (av) = L(L^{m}(v_{1}+v_{2})\\                   = L(L^{m} (v_{1} + L^{m}v_{2})\\                   = L(L^{m}v_{1} + L(L^{m}v_{2})\\                   = L^{m+1}(v_{1}) + L^{m+1}(v_{2})

6 0
2 years ago
Read 2 more answers
Corey gets paid $6 per hour to work at a snack stand. This weekend , he worked on both Saturday and Sunday. he made total of $48
Dahasolnce [82]

Answer:

5 hours

Step-by-step explanation:

1. Find out how many dollars he earned on Saturday

3 x 6 = 18

He earned 18 dollars on Saturday.

2. Subtract 18 from 48 since that is from Saturday, not Sunday

48 - 18 = 30

3. Divide 30 by 6 to see how many hours he worked on Sunday

30/6 = 5

6 0
3 years ago
A pizza chef begins to spin a constant volume of dough to make a pie by spinning and tossing the dough into the air, such that t
Alexxandr [17]

Answer:

a ) dAt/dt  =  50,24 in/min

dh/dt  =  -  0,125 in/min

Step-by-step explanation:

The area of the top is At :

At = π*r²

a)  Tacking derivatives with respect to time:

dAt/dt  =  2* π*r * dr/dt

At   t  =  t₁      r  = 16 in     and  dr/dt =  0,5

Then

dAt/dt  =  2*3,14*16*0,5   in/min

a ) dAt/dt  =  50,24 in/min

b) The volume of the cylinder is:

Vc =  π*r²*h     ( where h is the heigh of the cylinder )

Tacking derivatives with respect to time

dVc/dt  =  2* π*r*h*dr/dt  +  π*r²*dh/dt

But  dVc/dt  = 0  since the volume remains constant, then:

π*r²*dh/dt  = -  2* π*r*h*dr/dt

r*dh/dt  =  -  2*h*dr/dt

dh/dt  = - 2*0,5*2/16  in/min

dh/dt  =  -  0,125 in/min

4 0
3 years ago
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