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Degger [83]
3 years ago
8

Value of x in log5x = 4logx5 is

Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0
Log5 x=4 logx 5
Ln x/ln5=4(ln5 / ln x)                                 logx z=ln x / ln z
least common multiple=ln5 * ln x

ln²x=4ln²5
√(ln² x)=√(4 ln²5)
ln x=2ln 5
x=e^2ln5=25

Answer: x=25.

You might be interested in
Which axiom is used to prove that the product of two rational numbers is rational
aliina [53]

Answer:

First, a rational number is defined as the quotient between two integer numbers, such that:

N = a/b

where a and b are integers.

Now, the axiom that we need to use is:

"The integers are closed under the multiplication".

this says that if we have two integers, x and y, their product is also an integer:

if x, y ∈ Z ⇒ x*y ∈ Z

So, if now we have two rational numbers:

a/b and c/d

where a, b, c, and d ∈ Z

then the product of those two can be written as:

(a/b)*(c/d) = (a*c)/(b*d)

And by the previous axiom, we know that a*c is an integer and b*d is also an integer, then:

(a*c)/(b*d)

is the quotient between two integers, then this is a rational number.

5 0
4 years ago
Which ratio correctly compares 60 mm to 45 cm?
Agata [3.3K]
60 mm converts to 6 centimeters.
the ratio of 6 to 45 can be simplified to 
2 : 15
8 0
3 years ago
8 which of the following numbers Is Irrational?
snow_tiger [21]
It’s the square root of 2 (100%)
4 0
4 years ago
How many hours is 9:13pm from 10:00?
vivado [14]
From 10:00 am I would be 11 hours
5 0
4 years ago
The sides of a square all have a side length of y. Write a simplified area function in terms of y for a rectangle whose length i
gizmo_the_mogwai [7]

The simplified area function in terms of y for a rectangle is f(y)=2 y^{2}+4 y

<u>Solution:</u>

Given that length of each side of a square = y

Need to determine area of rectangle whose length is twice the length of the square and width is 2 units longer that the side length of square

Length of rectangle = twice of side length of square = 2 \times y = 2y

Width of rectangle = 2 + side length of square = 2 + y = y + 2

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle.}

On substituting length and width in formula for area, we get

\text { Area of rectangle }=2 y \times (y+2)=2 y^{2}+4 y

Hence function f(y)=2 y^{2}+4 y is represents area of required rectangle.

3 0
3 years ago
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