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GREYUIT [131]
3 years ago
9

Why do you think it is necessary for a student to pay back NSFAS loan after completing studies?

SAT
1 answer:
Likurg_2 [28]3 years ago
3 0

Answer:

Personally, I don't think education should be something that should be paid for especially in loans when most schools don't even teach you about the interest of loans or how money works in general.

Explanation:

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Using the z-distribution, it is found that the smallest sample size required to obtain the desired margin of error is of 4330.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem:

  • The estimate of the proportion is of \pi = 0.8.
  • The desired margin of error is of M = 0.01.
  • 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Then, we solve for n to find the minimum sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.8(0.2)}{n}}

0.01\sqrt{n} = 1.645\sqrt{0.8(0.2)}

\sqrt{n} = \frac{1.645\sqrt{0.8(0.2)}}{0.01}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.8(0.2)}}{0.01}\right)^2

n = 4329.6

Rounding up, the smallest sample size required to obtain the desired margin of error is of 4330.

To learn more about the z-distribution, you can take a look at brainly.com/question/12517818

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