Answer:
the angle that has the same measure as /2 is A
83, 76, 69, 62, 55, 48, 41, 34
Question:
If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.
Answer:
![Sin\theta = \frac{-15}{17}](https://tex.z-dn.net/?f=Sin%5Ctheta%20%3D%20%5Cfrac%7B-15%7D%7B17%7D)
![Tan\theta = \frac{15}{8}](https://tex.z-dn.net/?f=Tan%5Ctheta%20%3D%20%5Cfrac%7B15%7D%7B8%7D)
Step-by-step explanation:
Given
cos(θ) =-8/17
Required
sin(θ) = __
tan(θ) =__
The first step is to determine the length of the third side
Given that
![cos(\theta) = \frac{Adj}{Hyp}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%20%3D%20%5Cfrac%7BAdj%7D%7BHyp%7D)
Where Adj and Hyp represent Adjacent and Hypotenuse
![cos(\theta) = \frac{-8}{17}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%20%3D%20%5Cfrac%7B-8%7D%7B17%7D)
By comparison
![Adj = -8\ and\ Hyp = 17](https://tex.z-dn.net/?f=Adj%20%3D%20-8%5C%20and%5C%20Hyp%20%3D%2017)
Using Pythagoras
![Hyp^2 = Adj^2 + Opp^2](https://tex.z-dn.net/?f=Hyp%5E2%20%3D%20Adj%5E2%20%2B%20Opp%5E2)
By Substitution
![17^2 = (-8)^2 + Opp^2](https://tex.z-dn.net/?f=17%5E2%20%3D%20%28-8%29%5E2%20%2B%20Opp%5E2)
![289 = 64 + Opp^2](https://tex.z-dn.net/?f=289%20%3D%2064%20%2B%20Opp%5E2)
Subtract 64 from both sides
![289 - 64 = 64 - 64 + Opp^2](https://tex.z-dn.net/?f=289%20-%2064%20%3D%2064%20-%2064%20%2B%20Opp%5E2)
![225 = Opp^2](https://tex.z-dn.net/?f=225%20%3D%20Opp%5E2)
Take square roots of both sides
![\sqrt{225} = \sqrt{Opp^2}](https://tex.z-dn.net/?f=%5Csqrt%7B225%7D%20%3D%20%5Csqrt%7BOpp%5E2%7D)
![\sqrt{225} = Opp](https://tex.z-dn.net/?f=%5Csqrt%7B225%7D%20%3D%20Opp)
![15 = Opp](https://tex.z-dn.net/?f=15%20%3D%20Opp)
![Opp = 15](https://tex.z-dn.net/?f=Opp%20%3D%2015)
The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such
![Opp = -15](https://tex.z-dn.net/?f=Opp%20%3D%20-15)
From trigonometry
![Sin\theta = \frac{Opp}{Hyp}](https://tex.z-dn.net/?f=Sin%5Ctheta%20%3D%20%5Cfrac%7BOpp%7D%7BHyp%7D)
![Sin\theta = \frac{-15}{17}](https://tex.z-dn.net/?f=Sin%5Ctheta%20%3D%20%5Cfrac%7B-15%7D%7B17%7D)
Also from trigonometry
![Tan\theta = Sin\theta / Cos\theta](https://tex.z-dn.net/?f=Tan%5Ctheta%20%3D%20Sin%5Ctheta%20%2F%20Cos%5Ctheta)
![Tan\theta = \frac{-15}{17} / \frac{-8}{17}](https://tex.z-dn.net/?f=Tan%5Ctheta%20%3D%20%5Cfrac%7B-15%7D%7B17%7D%20%2F%20%5Cfrac%7B-8%7D%7B17%7D)
![Tan\theta = \frac{-15}{17} * \frac{-17}{8}](https://tex.z-dn.net/?f=Tan%5Ctheta%20%3D%20%5Cfrac%7B-15%7D%7B17%7D%20%2A%20%5Cfrac%7B-17%7D%7B8%7D)
![Tan\theta = \frac{-15 * -17}{17 * 8}](https://tex.z-dn.net/?f=Tan%5Ctheta%20%3D%20%5Cfrac%7B-15%20%2A%20-17%7D%7B17%20%20%2A%208%7D)
![Tan\theta = \frac{15 * 17}{17 * 8}](https://tex.z-dn.net/?f=Tan%5Ctheta%20%3D%20%5Cfrac%7B15%20%2A%2017%7D%7B17%20%20%2A%208%7D)
![Tan\theta = \frac{15}{8}](https://tex.z-dn.net/?f=Tan%5Ctheta%20%3D%20%5Cfrac%7B15%7D%7B8%7D)
Answer:
The pumpkin gained 33 pounds each week.
Step-by-step explanation:
Answer: okay i found it. it should be on the picture.
Step-by-step explanation: