Answer:
The probability that the intersection will come under the emergency program is 0.1587.
Step-by-step explanation:
Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.
Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.
For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.
Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).
The values of 
, the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program
Answer:
The number of viewers Network A expects will watch their show is 1.4 million viewers.
Step-by-step explanation:
The expected value is calculated by multiplying the possible outcomes by the probability of their occurrence and adding the results
Therefore, we have the expected value given by the following expression;
Estimated network A viewers where network B schedule top show = 1.1 million viewers
Estimated network A viewers where network B schedule a different show = 1.6 million viewers
Probability that Network B will air its top show = 0.4
Probability that Network B will air another show = 0.6
We therefore have;
Expected value, E of Network A viewers is therefore;
E = 1.1 × 0.4 + 1.6 × 0.6 = 0.44 + 0.96 = 1.4 million viewers.
Network A expects 1.4 million viewers will watch their show.
63 I think, you would subtract
Answer:
700 beads are in each bag.
Step-by-step explanation:
2(x+7)3X
I think... look it up though to be sure
