How do you show 239+132 integer form to polynomial form

Mathematics

1 answer:

TiliK225 [7]4 years ago

4 0

Answer:

The answer is "371"

Step-by-step explanation:

First polynomial value = 239

Second polynomial value = 132

Adding the value: = $239+ 132$

= $\boxed{\bold{371}}$

The final answer is 371, which is also known as monomial.

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$U(1)=1\\U(1\times2)=2\\U(1\times2\times3)=6\\U(1\times2\times3\times4)=U(24)=4\\U(1\times\boxed{2}\times3\times4\times\boxed{5})=0 \text{ because of } 2\times5=10\\U(1\times\boxed{2}\times3\times4\times\boxed{5}\times6)=0 \text{ because of } 2\times5=10\\....................\\....................\\U(1\times\boxed{2}\times3\times4\times\boxed{5}\times6\times...\times2019)=0 \text{ because of } 2\times5=10$

$\implies~U(1+1\times2+1\times2\times3+1\times2\times3\times4+...+1\times2\times3\times....\times2019)=\\=U(1+1\times2+1\times2\times3+1\times2\times3\times4) = ~~~\text{(The others terms have U = 0)}\\=U(1+2+6+24)=U(33)=\boxed{\bf3}$