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denis23 [38]
3 years ago
11

Which of the following pairs of lines are perpendicular? How do you know?

Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0
Hi mate:
Here is your explanation......


Which of the following is perpendicular to 32=16y+64x

Possible Answers:
y=−x/4+7

y=4x+7

y=−4x+7

y=x+1/4

y=x/4+7

Correct answer:
y=x/4+7

Explanation:
Two lines are perpendicular if and only if their slopes are negative reciprocals. To find the slope, we must put the equation into slope-intercept form, y=mx+b, where m equals the slope of the line. We begin by subtracting 16y from each side, giving us 32−16y=64x. Next, we subtract 32 from each side, giving us −16y=64x−32. Finally, we divide each side by −16, giving us y=−4x+2. We can now see that the slope is −4. Therefore, any line perpendicular to 32=16y+64x must have a slope of 1/4. Of the equations above, only y=x/4+7 has a slope of 1/4.

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does the assumption of a poisson distribution with a mean of 6.0 seem appropriate as a probability model for these data? use 0.0
Alenkasestr [34]

The Poisson distribution with a mean of 6.0 is an appropriate model.

<h3>What is mean?</h3>
  • In mathematics and statistics, the concept of mean is crucial. The most typical or average value among a group of numbers is called the mean.
  • It is a statistical measure of a probability distribution's central tendency along the median and mode. It also goes by the name "expected value."
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Hence, The Poisson distribution with a mean of 6.0 is an appropriate model.

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6 0
1 year ago
Write the equation in slope-intercept form of a line that has a slope of 1/3 and passes through the point (-6, 0).
Vesna [10]

Answer: y = 1/3x +2

Step-by-step explanation:

The equation of line in slope - point form is given as:

y - y_{1} = m ( x - x_{1} )

m = 1/3

y_{1} = 0

x_{1} = -6

substituting into the formula , we have

y - 0 = 1/3 ( x - {-6} )

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5 0
3 years ago
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F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
Butoxors [25]

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

5 0
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3 years ago
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AlladinOne [14]

Answer:

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Step-by-step explanation:

Convert 385 pounds into kg given the fact that 1 kg = 2.2 pounds.

385 : 2.2 =

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