Answer:
<h2>A. <em><u>2</u></em><em><u>1</u></em><em><u>4</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em></h2>
Step-by-step explanation:
<h3>#CarryOnLearning</h3>

Answer:
1.)
≈ 3.652
2.) I would say something about how the A in front of cos in the equation would change to 90, rather than stay 75 (in the equation for the step by step), but it would be easier to just use the Pythagorean theorem.
Step-by-step explanation:
I think we may have the same class so hopefully this helps:
1.)
--> law of cosines formula.
--> plugged in numbers; when you draw the triangle, the included angle would be A, and the opposite side would be a. B and b, and C and c are opposite each other. In this case, a is the hypotenuse.
--> in between steps.
--> more simplifying.
--> answer
2.) This one is just an explanation: The 75 in the equation is the given angle, which is a. If this changes, it would just change in the equation too. And obviously, if it's 90 degrees, you can just use Pythagorean theorem a^2+b^2=c^2.
Good luck! :)
Answer:
The answer is x=294 (B)
Step-by-step explanation:
Remember, all interior angles of a hexagon add to 720.
So add all the given numbers first.
92+100+94+140+x= 720
426+x=720
-426 from both sides
x= 294
I know this is a week later since you posted the question, sorry.
Answer:
10)$38.50
11)D
Step-by-step explanation:
10) n = no. of rides
f(n) + g(n) = 1 + 2.5n
when n=15, 1 + 2.5(15)
= $38.50
11)f(x) = 4x³+3x²-5x+20
g(x) = 9x³-4x²+10x-55
(g-f)(x)=9x³-4x²+10x-55-(4x³
+3x²-5x+20)
= 9x³-4x²+10x-55-4x³
-3x²+5x-20
= 5x³-7x²+15x-75
(Correct me if i am wrong)
From the information provided by the statement, you know that
*Ann draws 2/16 of the playground
*Susan draws 6/16 of the playground because she draws 3 times as much as Ann so

*Louise draws 3/16 because she draws half as much as Susan, so

*Sam draws 2/16 because she draws 1 less section than Louise

Now, let x be the fraction of the playground that still needs to be drawn. Then, you have

Therefore, 3/16 of the playground still needs to be drawn.