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3 years ago

Help me with this please!!!!!!

Mathematics

1 answer:

Gnoma [55]3 years ago

3 0

Answer:

False

Step-by-step explanation:

If the point (-4,3) is the center of a circle and that circles perimeter contains the point (4,9) there it no way that the point (2,-5) could be in that circle

Hope this is right heh, I'm not really good with these type of problems. byeee <3

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Yessir help a girl out!

REY [17]

Answer:

3rd option (not regular)

Step-by-step explanation:

all the other options are not true

4 0

3 years ago

Please somebody else help me to do . I will mark the correct answer as a brainiest

vodomira [7]

there is your answer follow and mark me as brainliest 

4 0

3 years ago

Write an equation of the line that is perpendicular to 3x + 9y = 7 and passes through the point (6, 4)

andrezito [222]

The perpendicular line will have the x and y coefficients swapped and one of them negated. We can write the desired line as
9(x -6) -3(y -4) = 0
where the coordinates of the point of interest are (6, 4).
Dividing by 3, this is
3(x -6) -(y -4) = 0
3x -y = 14

An equation for the line of interest is ...
3x -y = 14

8 0

3 years ago

Read 2 more answers

If you start with 85 milligrams of Chromium 51, used to track red blood cells, which

zysi [14]

About 92 days are taken for 90 % of the material to decay.

The mass of radioisotopes ( $m$ ), measured in milligrams, decreases exponentially in time ( $t$ ), measured in days. The model that represents such decrease is described below:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ (1)

Where:

$m_{o}$ - Initial mass, in milligrams.
$m(t)$ - Current mass, in milligrams.
$\tau$ - Time constant, in days.

In addition, the time constant is defined in terms of half-life ( $t_{1/2}$ ), in days:

$\tau = \frac{t_{1/2}}{\ln 2}$ (2)

If we know that $m_{o} = 85\,mg$ , $t_{1/2} = 27.7\,d$ and $m(t) = 8.5\,mg$ , then the time required for decaying is:

$\tau = \frac{t_{1/2}}{\ln 2}$

$\tau = \frac{27.7\,d}{\ln 2}$

$\tau \approx 39.963\,d$

$t = -\tau \cdot \ln \frac{m(t)}{m_{o}}$

$t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}$

$t\approx 92.018\,d$

About 92 days are taken for 90 % of the material to decay.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0

2 years ago

Please help with these math questions part one

katrin [286]

V of cone=(1/3)(pi)(h)(r^2)
V of cylinder=(pi)(h)(r^2)

1.
r=6
h=10
v=(1/3)(pi)(10)(6^2)
v=1/3pi10(36)
v=1/3pi360
v=120pi
answer is B

2.
r=d/2
d=10
10/2=5=r
V=(3.14)(5)(5^2)
V=3.14(125)
V=392.5
answer is B

3. 9.2, 3.7
V=(pi)(9.2)(3.7^2)
V=(pi)(9.2)(13.69)
V=(pi)(125.948)
input 125.948

4. v=(1/3)(pi)(12)(3^2)
V=(1/3)(pi)(12)(9)
V=(pi)(12)(3)
V=pi(36
v=36pi
v=36(3.14)
V=113.04

input 113.04

ANSERS
1.B
2.B
3. 129.948
4. 113.04

3 0

3 years ago