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snow_lady [41]
3 years ago
5

a leading coefficient of 1 has zeros of x = 3 and x = −2, what is the factored form of this function?

Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

factors are x-3 and x+2

Step-by-step explanation:

If the zeros of the functions are x = 3 and x = -2, hence the factors in terms of x are (x-3) and (x+2)

Get the function

(x-3)(x+2)

= x^2+2x-3x-6

= x^2 - x - 6

Hence the required function is x^2 - x - 6 and the factors are x-3 and x+2

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3x^2+48=0, solve the equation
MAXImum [283]

Answer:

16 + x2 = 0     (16)

I THINK

Step-by-step explanation: Simplifying

3x2 + 48 = 0

Reorder the terms:

48 + 3x2 = 0

Solving

48 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-48' to each side of the equation.

48 + -48 + 3x2 = 0 + -48

Combine like terms: 48 + -48 = 0

0 + 3x2 = 0 + -48

3x2 = 0 + -48

Combine like terms: 0 + -48 = -48

3x2 = -48

Divide each side by '3'.

x2 = -16

Simplifying

x2 = -16

Reorder the terms:

16 + x2 = -16 + 16

Combine like terms: -16 + 16 = 0

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3 years ago
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Step-by-step explanation:

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