a leading coefficient of 1 has zeros of x = 3 and x = −2, what is the factored form of this function?
1 answer:
Answer:
factors are x-3 and x+2
Step-by-step explanation:
If the zeros of the functions are x = 3 and x = -2, hence the factors in terms of x are (x-3) and (x+2)
Get the function
(x-3)(x+2)
= x^2+2x-3x-6
= x^2 - x - 6
Hence the required function is x^2 - x - 6 and the factors are x-3 and x+2
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