a leading coefficient of 1 has zeros of x = 3 and x = −2, what is the factored form of this function?
1 answer:
Answer:
factors are x-3 and x+2
Step-by-step explanation:
If the zeros of the functions are x = 3 and x = -2, hence the factors in terms of x are (x-3) and (x+2)
Get the function
(x-3)(x+2)
= x^2+2x-3x-6
= x^2 - x - 6
Hence the required function is x^2 - x - 6 and the factors are x-3 and x+2
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Step-by-step explanation:
Substitute the value of the variable into the expression and simplify.
Exact Form: a
=
6,
2
3
Decimal Form:
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=
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Subtract 50 from both sides:


hope this helps!
The number -5 is anything but natural number.
It is an integer (Z) ,a rational number (Q) and a real number (R) .
Answer:
6+2+9+5+2+3+6+3 = 36
Step-by-step explanation:
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