25 Points Asap Write a Java program named Light.java that displays a light bulb shown below:

Write an application that determines whether the first two files are located in the same folder as the third one. The program sh

marissa [1.9K]

Answer:

The program in Python is as follows:

fname1 = input("Filepath 1: ").lower()

fname2 = input("Filepath 2: ").lower()

fname3 = input("Filepath 3: ").lower()

f1dir = ""; f2dir = ""; f3dir = ""

fnamesplit = fname1.split("/")

for i in range(len(fnamesplit)-1):

f1dir+=fnamesplit[i]+"/"

fnamesplit = fname2.split("/")

for i in range(len(fnamesplit)-1):

f2dir+=fnamesplit[i]+"/"

fnamesplit = fname3.split("/")

for i in range(len(fnamesplit)-1):

f3dir+=fnamesplit[i]+"/"

if f1dir == f2dir == f3dir:

print("Files are in the same folder")

else:

print("Files are in the different folder")

Explanation:

The next three lines get the file path of the three files

fname1 = input("Filepath 1: ").lower()

fname2 = input("Filepath 2: ").lower()

fname3 = input("Filepath 3: ").lower()

This initializes the directory of the three files to an empty string

f1dir = ""; f2dir = ""; f3dir = ""

This splits file name 1 by "/"

fnamesplit = fname1.split("/")

This iteration gets the directory of file 1 (leaving out the file name)

for i in range(len(fnamesplit)-1):

f1dir+=fnamesplit[i]+"/"

This splits file name 2 by "/"

fnamesplit = fname2.split("/")

This iteration gets the directory of file 2 (leaving out the file name)

for i in range(len(fnamesplit)-1):

f2dir+=fnamesplit[i]+"/"

This splits file name 3 by "/"

fnamesplit = fname3.split("/")

This iteration gets the directory of file 3 (leaving out the file name)

for i in range(len(fnamesplit)-1):

f3dir+=fnamesplit[i]+"/"

This checks if the file directories hold the same value

This is executed, if yes

if f1dir == f2dir == f3dir:

print("Files are in the same folder")

This is executed, if otherwise

else:

print("Files are in the different folder")

5 0

3 years ago

Ndcdeviceid?????????????????????

butalik [34]

YESS

Explanation:

YESSssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

7 0

2 years ago

On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance

Stels [109]

Answer:

#include <stdio.h>

int main()

{

float your_value1, your_value2, your_value3, your_value4, your_value5;

printf("Enter a frequency: ");

scanf_s("%f", &your_value1);//storing initial key frequency in your value 1

float r = 2.0 / 12;//typing 2.0 so it is treated as float and not int

your_value2 = your_value1 * r * 1; //initial*r*n

your_value3 = your_value1 * r * 2; //initial*r*n

your_value4 = your_value1 * r * 3; //initial*r*n

your_value5 = your_value1 * r * 4; //initial*r*n

printf("%0.2f %0.2f %0.2f %0.2f %0.2f", your_value1, your_value2, your_value3, your_value4, your_value5);

return 0;

}

Explanation:

The purpose of this exercise is to make you understand the difference between float and int. float variables are used when you need decimals in your calculations. int is used when you need integers. The problem in this exercise was the formulation of r. Now r is = 2/12, this means that when we type r as that, the computer assumes that it is an integer and treats it as such. So, it will convert the 0.166667 into 0. To overcome this, all you have to do is type 2.0 instead of 2 alone.

The %0.2 command restricts the float variable to 2 decimal places. By default, it has 6 decimal places.

I have used the function scanf_s instead of scanf simply because my compiler does not work with scanf.

3 0

3 years ago

This is an example of ______________ of variables:

Sedbober [7]

Answer:

Encapsulation is an example of variables

6 0

3 years ago

The value of the mathematical constant e can be expressed as an infinite series: e=1+1/1!+1/2!+1/3!+... Write a program that app

LUCKY_DIMON [66]

Answer:

// here is code in c++ to find the approx value of "e".

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

double fact(int n){

double f =1.0;

// if n=0 then return 1

if(n==0)

return 1;

for(int a=1;a<=n;++a)

f = f *a;

// return the factorial of number

return f;

}

// driver function

int main()

{

// variable

int n;

double sum=0;

cout<<"enter n:";

// read the value of n

cin>>n;

// Calculate the sum of the series

for (int x = 0; x <= n; x++)

{

sum += 1.0/fact(x);

}

// print the approx value of "e"

cout<<"Approx Value of e is: "<<sum<<endl;

return 0;

}

Explanation:

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

Output:

enter n:12

Approx Value of e is: 2.71828

6 0

3 years ago